How to prevent a class from being inheritable, in C++

[Saumya]

Hi,

I didn't know how else to express myself in the subject line, but what
I want to know is this: <b>I have a class A, so what do I have to do
to ensure that no one can derive from it?</b>

Saumya

[Datta Patil]

"Saumya" <sa**********@y ahoo.com> wrote in message
news:e9******** *************** ***@posting.goo gle.com...

Not a very technical reason pal, but it just struck me while I was
learning Java and encountered the "final" keyword there.

U mean how to simulate final java class concept in c++.....here is
program.I guess its similar to creating singleton pattern

// Make ctor private so that class cannot be inheriated

//Use static member function to create object of its own which will return
ptr to same class obj

#include <iostream.h>

class X{

private :

int x;

X(); // private ctor

public :

static X* getMePrivateObj ect(); // this will help me creating handle rather
for normal object

};
X::X(){

cout<<"in constructor"<<e ndl;

x=0;

};
X* X::getMePrivate Object(){

X *pMyP = new X();

return pMyP;

};

/*class Y : public X //cannot do this as X has private ctor

{

public:

Y(){}

void print(){ cout<<"Display me if u can";}

};

*/

void main(void){

X *pMyP = X::getMePrivate Object();

//Rest of ur code

}

[Datta Patil]

Check this program....Clas s X acts like final class in java.

#include <iostream.h>
class X{
private :
int x;
X(); // private ctor
public :
static X* getMePrivateObj ect(); // this will help me creating handle rather
for normal object
};
X::X(){
cout<<"in constructor"<<e ndl;
x=0;
};
X* X::getMePrivate Object(){
X *pMyP = new X();
return pMyP;
};
/*class Y : public X //cannot do this as X has private ctor
{
public:
Y(){}
void print(){ cout<<"Display me if u can";}
};
*/
void main(void){
X *pMyP = X::getMePrivate Object();
//Rest of ur code
}
Njoy,

Datta Patil