File associated with fstream object?

[Sanyi Benczik]

Is there a way to obtain the name of the file associated with a fstream
object?

For example if I have

using namespace std;
ofstream file("test.txt" );

is there a function which evaluates to "test.txt"?

Thx,
Sanyi

[Jack Klein]

On Tue, 20 Jan 2004 01:49:44 -0500, Sanyi Benczik
<sb******@hotma il.com> wrote in comp.lang.c++:

Is there a way to obtain the name of the file associated with a fstream
object?

For example if I have

using namespace std;
ofstream file("test.txt" );

is there a function which evaluates to "test.txt"?

Thx,
Sanyi

There is no way to do this using standard C++. There might or might
not be a non-standard platform specific extension provided by your
compiler/OS combination. On some platforms, a single file may have
more than one name.

Of course you could always build an object that contained a
std::string with the name and a stream reference.

--
Jack Klein
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[Dietmar Kuehl]

Jack Klein <ja*******@spam cop.net> wrote:

On some platforms, a single file may have
more than one name.
.... or none at all:

std::ofstream tmpfile("mytemp file");
std::remove("my tempfile");

This is fine eg. on POSIX platforms and, except for the use of the hardcoded
name, a pretty common technique to create temporary files which are to be
removed when the program dies for whatever reason.
Of course you could always build an object that contained a
std::string with the name and a stream reference.

.... or attach the name to your file object:

int const index = std::ios_base:: xalloc();
std::string filename("file. name");
std::ofstream file(filename.c _str());
file.pword(inde x) = const_cast<char *>(filename.c_s tr());
// ...
char const* name = static_cast<cha r*>(file.pword( index));
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