Is it possible to store a pointer to a template function?
eg,
template<class T> fooFunc() {...}
[ptr_to_template _function] fptr = fooFunc; // <--
I couldn't find any info here, not even in the forums: http://www.function-pointer.org/
Thanks,
Suzanne 5 2965
Suzanne Vogel wrote: Is it possible to store a pointer to a template function?
eg, template<class T> fooFunc() {...}
[ptr_to_template _function] fptr = fooFunc; // <--
I couldn't find any info here, not even in the forums: http://www.function-pointer.org/
Thanks, Suzanne
What seems to be the problem ?
The example you start with has no dependance on the template.
I created a second example that might be more like what you're after ...
see below.
template<class T> int fooFunc()
{
return 0;
}
class x;
int (* ptr_fooFunc)() = &fooFunc<x>;
template<class T> T * zooFunc()
{
return 0;
}
template<class T>
struct Stuff
{
static T* (* ptr_zooFunc)();
};
template<class T>
T* (* Stuff<T>::ptr_z ooFunc)() = &zooFunc<T>;
int main()
{
ptr_fooFunc();
(*Stuff<int>::p tr_zooFunc)();
}
On Fri, 16 Jan 2004 18:46:37 -0500 in comp.lang.c++, Suzanne Vogel
<su************ *@hotmail.com> was alleged to have written: Is it possible to store a pointer to a template function?
eg, template<cla ss T> fooFunc() {...}
[ptr_to_template _function] fptr = fooFunc; // <--
No. A pointer must be a pointer to a specific type. A function
pointer must be a pointer to a specific function signature. Template
instantiations have basically no relationship to each other. Related
types are created by inheritance. What are you trying to accomplish?
Suzanne Vogel wrote: Is it possible to store a pointer to a template function?
eg, template<class T> fooFunc() {...}
[ptr_to_template _function] fptr = fooFunc; // <-- ...
Strictly speaking, 'fooFunc' is not a template function. It is a
function template. It is not possible to have a pointer to function
template. However, once the template is specialized it becomes ordinary
function and you can create a pointer to it.
There are different ways to specialize a function template. It can be
done by explicit specification of template arguments. Or it can be done
implicitly by compiler (template argument deduction). In fact, when you
do something like this
SomePtrToFuncti onType fptr = fooFunc;
(where 'fooFunc' is a function template) the compiler will attempt to
perform template argument deduction based on the target type
('SomePtrToFunc tionType') in order to obtain compatible specialization
of 'fooFunc' template.
But again, even if it works, if creates a pointer to a concrete
specialization of the template, not to the function template itself.
There is no such thing in C++ as 'pointer to template'.
--
Best regards,
Andrey Tarasevich
Thanks to all those who responded...
David Harmon wrote: On Fri, 16 Jan 2004 18:46:37 -0500 in comp.lang.c++, Suzanne Vogel <su************ *@hotmail.com> was alleged to have written:
Is it possible to store a pointer to a template function?
eg, template<clas s T> fooFunc() {...}
[ptr_to_template _function] fptr = fooFunc; // <--
No. A pointer must be a pointer to a specific type. A function pointer must be a pointer to a specific function signature. Template instantiations have basically no relationship to each other. Related types are created by inheritance. What are you trying to accomplish?
Okay, thanks.
Here's what I was trying to accomplish: I wanted to store a hashmap of
pointers to template functions, indexed by classname:
std::hash_map< std::string, [ptr_to_template _func] > mFuncPtrs;
Each of these pointers to a template function came from here:
template<class T>
class Wrapper
{
public:
template<class S>
void f() {.....} //acts on types S and T together
}
To store a pointer to a template function for class Foo, I'd do this:
class Foo {...}
mFuncPtrs["Foo"] = [ptr_to_Wrapper< Foo>::f()];
But, apparently this is impossible.
Suzanne
On Sat, 17 Jan 2004 01:23:37 -0500 in comp.lang.c++, Suzanne Vogel
<su************ *@hotmail.com> was alleged to have written: Here's what I was trying to accomplish: I wanted to store a hashmap of pointers to template functions, indexed by classname:
std::hash_ma p< std::string, [ptr_to_template _func] > mFuncPtrs;
OK, I don't know if this idea gets you closer or not:
Create a base class. The function you are going to call is a virtual
function in the base class. The template classes are derived from the
base, and override the virtual function. The map contains (base*)
pointers.
I don't see how you intend to get from the function pointer to a
type-safe invocation of it. If you wish to throw away type safety, then
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