A have a long integer class. The built integer type within a conditional
statement returns bool false for int i=0 and bool true for any other non
zero value. I want my long integer class to have similar behavior. My
class looks like this:
#ifndef long_int_H
#define long_int_H
#include <string>
using namespace std;
typedef valarray<comple x<double> > VCD;
typedef valarray<comple x<float> > VCF;
typedef valarray<float> VAF;
typedef complex<double> COMPLEX;
const unsigned MAX_SIZE=104857 6; //2^20
enum base{BIN=2, OCT=8, DEC=10, HEX=16};
base RAD=DEC;
class long_int{
friend ostream& operator<<(ostr eam& , const long_int& );
friend istream& operator>>(istr eam& , long_int& );
private:
base _radix;
string _str ;
int _len ;
long_int x_digit(const int&)const;
void x_radix();
void carry(VAF&)cons t;
string put_str()const;
static char itoc(const int& );
static int ctoi(const char&);
public:
long_int(base radix=RAD):_rad ix(radix),_str( "0"),_len(1 ){}
explicit long_int(const string& s, base radix=RAD);
explicit long_int(const signed long& n, base radix=RAD);
long_int& operator=(const long_int& v);
long_int& operator=(const string& s);
long_int& operator=(const signed long& n);
long_int& operator+=(cons t long_int&);
long_int& operator++();
long_int operator++(int) ;
long_int& operator-=(const long_int&);
long_int& operator--();
long_int operator--(int);
long_int& operator*=(cons t long_int&);
long_int& operator/=(const long_int&);
long_int& operator%=(cons t long_int&);
long_int operator!()cons t;
long_int operator-()const;
long_int operator+()cons t;
long_int sqrt()const;
long_int abs()const;
void radix_convert(b ase radix=RAD);
int size()const;
bool operator<(const long_int&)const ;
bool operator>(const long_int&)const ;
bool operator==(cons t long_int&)const ;
bool operator!=(cons t long_int&)const ;
bool operator<=(cons t long_int&)const ;
bool operator>=(cons t long_int&)const ;
bool is_odd()const;
};
#endif
In my attempts to implement the bool functionality if I add "operator
bool()const{ if(*this==0) return false; else return true; }" below the bool
operators the compiler gives multiple warnings with the "<", "<=" and "%"
bool operators specifically "unsafe use of type 'bool' in operation". ( If
I remove the explicit qualifier from the second constructor I get multiple
errors --- "two overloads have similar conversions".) The warnings are
occuring in conditional statements within the definition of the arithmatic
operators. Are these warnings significant? Is this the correct way to
implement bool functionality?
3  2604 
"Pierre Espenan" <wh************ **@yahoo.com> skrev i en meddelelse
news:91******** ***********@new sread1.news.pas .earthlink.net. .. A have a long integer class. The built integer type within a conditional
statement returns bool false for int i=0 and bool true for any other non
zero value. I want my long integer class to have similar behavior. My
class looks like this:
#ifndef long_int_H
#define long_int_H
#include <string>
using namespace std;
typedef valarray<comple x<double> > VCD;
typedef valarray<comple x<float> > VCF;
typedef valarray<float> VAF;
typedef complex<double> COMPLEX;
const unsigned MAX_SIZE=104857 6; //2^20
enum base{BIN=2, OCT=8, DEC=10, HEX=16};
base RAD=DEC;
class long_int{
friend ostream& operator<<(ostr eam& , const long_int& );
friend istream& operator>>(istr eam& , long_int& );
private:
base _radix;
string _str ;
int _len ;
long_int x_digit(const int&)const;
void x_radix();
void carry(VAF&)cons t;
string put_str()const;
static char itoc(const int& );
static int ctoi(const char&);
public:
long_int(base radix=RAD):_rad ix(radix),_str( "0"),_len(1 ){}
explicit long_int(const string& s, base radix=RAD);
explicit long_int(const signed long& n, base radix=RAD);
long_int& operator=(const long_int& v);
long_int& operator=(const string& s);
long_int& operator=(const signed long& n);
long_int& operator+=(cons t long_int&);
long_int& operator++();
long_int operator++(int) ;
long_int& operator-=(const long_int&);
long_int& operator--();
long_int operator--(int);
long_int& operator*=(cons t long_int&);
long_int& operator/=(const long_int&);
long_int& operator%=(cons t long_int&);
long_int operator!()cons t;
long_int operator-()const;
long_int operator+()cons t;
long_int sqrt()const;
long_int abs()const;
void radix_convert(b ase radix=RAD);
int size()const;
bool operator<(const long_int&)const ;
bool operator>(const long_int&)const ;
bool operator==(cons t long_int&)const ;
bool operator!=(cons t long_int&)const ;
bool operator<=(cons t long_int&)const ;
bool operator>=(cons t long_int&)const ;
bool is_odd()const;
};
#endif
In my attempts to implement the bool functionality if I add "operator
bool()const{ if(*this==0) return false; else return true; }" below the
bool operators the compiler gives multiple warnings with the "<", "<=" and "%"
bool operators specifically "unsafe use of type 'bool' in operation".
( If I remove the explicit qualifier from the second constructor I get multiple
errors --- "two overloads have similar conversions".) The warnings are
occuring in conditional statements within the definition of the arithmatic
operators. Are these warnings significant? Is this the correct way to
implement bool functionality?
First, why don't you write your operator as
operator bool()const{ return *this!=0; }
this is more concise.
Second, your class does not permit you to compare your long_int with
ordinary integers. To do so, your class needs a constructor long_int(int i)
which is not explicit.
Third, your comparison functions should really be friends - as in
friend bool operator<(const long_int& lhs,const long_int& rhs);
this will enable you to write code such as:
int i;
long_int j;
....
if (i > j) ....
Fourth, there are problems with bool that suggest you better dont provide
such an operator. Instead use a conversion to void* const:
operator void* const(){ return *this!=0 ? this:0; }
This enables you to write
long_int j(0);
....
if (j) ...
Last, I do not see why you choose to expose your representation of radix to
the enduser. I would have opted for a radix-free long_int representation,
choosing a radix only when when outputting or inputting the numbers.
Kind regards
Peter
Peter Koch Larsen wrote: "Pierre Espenan" <wh************ **@yahoo.com> skrev i en meddelelse
news:91******** ***********@new sread1.news.pas .earthlink.net. ..
A have a long integer class. The built integer type within a conditional
statement returns bool false for int i=0 and bool true for any other non
zero value. I want my long integer class to have similar behavior. My
class looks like this:
#ifndef long_int_H
#define long_int_H
#include <string>
using namespace std;
typedef valarray<comple x<double> > VCD;
typedef valarray<comple x<float> > VCF;
typedef valarray<float> VAF;
typedef complex<double> COMPLEX;
const unsigned MAX_SIZE=104857 6; //2^20
enum base{BIN=2, OCT=8, DEC=10, HEX=16};
base RAD=DEC;
class long_int{
friend ostream& operator<<(ostr eam& , const long_int& );
friend istream& operator>>(istr eam& , long_int& );
private:
base _radix;
string _str ;
int _len ;
long_int x_digit(const int&)const;
void x_radix();
void carry(VAF&)cons t;
string put_str()const;
static char itoc(const int& );
static int ctoi(const char&);
public:
long_int(base radix=RAD):_rad ix(radix),_str( "0"),_len(1 ){}
explicit long_int(const string& s, base radix=RAD);
explicit long_int(const signed long& n, base radix=RAD);
long_int& operator=(const long_int& v);
long_int& operator=(const string& s);
long_int& operator=(const signed long& n);
long_int& operator+=(cons t long_int&);
long_int& operator++();
long_int operator++(int) ;
long_int& operator-=(const long_int&);
long_int& operator--();
long_int operator--(int);
long_int& operator*=(cons t long_int&);
long_int& operator/=(const long_int&);
long_int& operator%=(cons t long_int&);
long_int operator!()cons t;
long_int operator-()const;
long_int operator+()cons t;
long_int sqrt()const;
long_int abs()const;
void radix_convert(b ase radix=RAD);
int size()const;
bool operator<(const long_int&)const ;
bool operator>(const long_int&)const ;
bool operator==(cons t long_int&)const ;
bool operator!=(cons t long_int&)const ;
bool operator<=(cons t long_int&)const ;
bool operator>=(cons t long_int&)const ;
bool is_odd()const;
};
#endif
In my attempts to implement the bool functionality if I add "operator
bool()const { if(*this==0) return false; else return true; }" below the
bool
operators the compiler gives multiple warnings with the "<", "<=" and "%"
bool operators specifically "unsafe use of type 'bool' in operation".
( If
I remove the explicit qualifier from the second constructor I get multiple
errors --- "two overloads have similar conversions".) The warnings are
occuring in conditional statements within the definition of the arithmatic
operators. Are these warnings significant? Is this the correct way to
implement bool functionality?
First, why don't you write your operator as
operator bool()const{ return *this!=0; }
this is more concise.
Right on.
Second, your class does not permit you to compare your long_int with
ordinary integers. To do so, your class needs a constructor long_int(int i)
which is not explicit.
Third, your comparison functions should really be friends - as in
Or, since I personally don't like friend functions, just make sure your
class provides enough public accessors for the comparisons to be
performed by functions outside the class.
friend bool operator<(const long_int& lhs,const long_int& rhs);
this will enable you to write code such as:
int i;
long_int j;
...
if (i > j) ....
Fourth, there are problems with bool that suggest you better dont provide
such an operator. Instead use a conversion to void* const:
operator void* const(){ return *this!=0 ? this:0; }
This enables you to write
long_int j(0);
...
if (j) ...
That's a fantastic idea I will be stealing for my own code. :)
Last, I do not see why you choose to expose your representation of radix to
the enduser. I would have opted for a radix-free long_int representation,
choosing a radix only when when outputting or inputting the numbers.
Kind regards
Peter
"Peter Koch Larsen" <pk*@mailme.d k> wrote in message
news:3f******** **************@ dread14.news.te le.dk...
"Pierre Espenan" <wh************ **@yahoo.com> skrev i en meddelelse
news:91******** ***********@new sread1.news.pas .earthlink.net. .. A have a long integer class. The built integer type within a
conditional statement returns bool false for int i=0 and bool true for any other non
zero value. I want my long integer class to have similar behavior. My
class looks like this:
#ifndef long_int_H
#define long_int_H
#include <string>
using namespace std;
typedef valarray<comple x<double> > VCD;
typedef valarray<comple x<float> > VCF;
typedef valarray<float> VAF;
typedef complex<double> COMPLEX;
const unsigned MAX_SIZE=104857 6; //2^20
enum base{BIN=2, OCT=8, DEC=10, HEX=16};
base RAD=DEC;
class long_int{
friend ostream& operator<<(ostr eam& , const long_int& );
friend istream& operator>>(istr eam& , long_int& );
private:
base _radix;
string _str ;
int _len ;
long_int x_digit(const int&)const;
void x_radix();
void carry(VAF&)cons t;
string put_str()const;
static char itoc(const int& );
static int ctoi(const char&);
public:
long_int(base radix=RAD):_rad ix(radix),_str( "0"),_len(1 ){}
explicit long_int(const string& s, base radix=RAD);
explicit long_int(const signed long& n, base radix=RAD);
long_int& operator=(const long_int& v);
long_int& operator=(const string& s);
long_int& operator=(const signed long& n);
long_int& operator+=(cons t long_int&);
long_int& operator++();
long_int operator++(int) ;
long_int& operator-=(const long_int&);
long_int& operator--();
long_int operator--(int);
long_int& operator*=(cons t long_int&);
long_int& operator/=(const long_int&);
long_int& operator%=(cons t long_int&);
long_int operator!()cons t;
long_int operator-()const;
long_int operator+()cons t;
long_int sqrt()const;
long_int abs()const;
void radix_convert(b ase radix=RAD);
int size()const;
bool operator<(const long_int&)const ;
bool operator>(const long_int&)const ;
bool operator==(cons t long_int&)const ;
bool operator!=(cons t long_int&)const ;
bool operator<=(cons t long_int&)const ;
bool operator>=(cons t long_int&)const ;
bool is_odd()const;
};
#endif
In my attempts to implement the bool functionality if I add "operator
bool()const{ if(*this==0) return false; else return true; }" below the bool operators the compiler gives multiple warnings with the "<", "<=" and
"%" bool operators specifically "unsafe use of type 'bool' in operation".
( If I remove the explicit qualifier from the second constructor I get
multiple errors --- "two overloads have similar conversions".) The warnings are
occuring in conditional statements within the definition of the
arithmatic operators. Are these warnings significant? Is this the correct way to
implement bool functionality?
First, why don't you write your operator as
operator bool()const{ return *this!=0; }
Thanks, I did but I had to do it like this:
operator bool()const{ return *this!=long_int (0); }
even after I took the explicit qualifier off the integer ctor
this is more concise.
Second, your class does not permit you to compare your long_int with
ordinary integers. To do so, your class needs a constructor long_int(int
i) which is not explicit.
I took off the explicit
Third, your comparison functions should really be friends - as in
friend bool operator<(const long_int& lhs,const long_int& rhs);
this will enable you to write code such as:
int i;
long_int j;
...
if (i > j) ....
I didn't do this yet but I'll look into it.
Fourth, there are problems with bool that suggest you better dont provide
such an operator. Instead use a conversion to void* const:
operator void* const(){ return *this!=0 ? this:0; }
I had to do it the same way:
operator void* const(){ return *this!=long_int (0) ? this:0; }
to get it to work.
This enables you to write
long_int j(0);
...
if (j) ...
Last, I do not see why you choose to expose your representation of radix
to the enduser. I would have opted for a radix-free long_int representation,
choosing a radix only when when outputting or inputting the numbers.
I want the user to be able to change the radix.
The default radix is decimal. The overloaded cin operator takes the radix
of the long_int into account when inputting.
The radix can be converted between all four bases, for example:
100!=9332621544 394415268169923 885626670049071 596826438162146 859296389521759 9
993229915
608941463976156 518286253697920 827223758251185 210916864000000 000000000000000 0
00 (DEC) =
1B30964EC395DC2 4069528D54BBDA4 0D16E966EF9A70E B21B5B2943A321C DF10391745570CC A
9420
C6ECB3B72ED2EE8 B02EA2735C61A00 000000000000000 0000000 (HEX)
Kind regards
Peter
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