Hi,
I have an array:
double *array = new double[50];
Well, I have 2 actually.
double *array2 = new double[50];
Say 'array' is poulated with 'doubles'. How do I copy all of array's values
into 'array2'?
TIA,
-- JA
5  1318 
"J" <ni********@gl. gl> wrote in message
news:Xn******** **************@ 130.215.36.210. .. Hi,
I have an array:
double *array = new double[50];
Well, I have 2 actually.
double *array2 = new double[50];
Say 'array' is poulated with 'doubles'. How do I copy all of array's
values into 'array2'?
TIA,
-- JA
memcpy(array2, array, 50 * sizeof(double)) ;
Thanks my friend, totally forgot memcpy. (Haven't programmed in awhile!!)
- JA
"Thomas Wintschel" <th******@telus .net> wrote in news:PHTyb.9129 5
$oN2.40286@edtn ps84:
"J" <ni********@gl. gl> wrote in message
news:Xn******** **************@ 130.215.36.210. .. Hi,
I have an array:
double *array = new double[50];
Well, I have 2 actually.
double *array2 = new double[50];
Say 'array' is poulated with 'doubles'. How do I copy all of array's
values into 'array2'?
TIA,
-- JA
memcpy(array2, array, 50 * sizeof(double)) ;
"J" <ni********@gl. gl> wrote in message
news:Xn******** **************@ 130.215.36.210. .. Hi,
I have an array:
double *array = new double[50];
Well, I have 2 actually.
double *array2 = new double[50];
Say 'array' is poulated with 'doubles'. How do I copy all of array's
values into 'array2'?
std::copy(array , array + 50, array2);
This assumes that 'array' and 'array2' each have at least
50 elements, and that all elements of 'array' have valid
values.
'std::copy()' is declared by <algorithm>.
-Mike
Thomas Wintschel wrote: "J" <ni********@gl. gl> wrote in message
news:Xn******** **************@ 130.215.36.210. ..
Hi,
I have an array:
double *array = new double[50];
Well, I have 2 actually.
double *array2 = new double[50];
Say 'array' is poulated with 'doubles'. How do I copy all of array's
values
into 'array2'?
memcpy(array2, array, 50 * sizeof(double)) ;
Hmm...whats memcpy doing in a c++ forum :-)
"Roy Varghese" <rv*******@user sDOTsf.net> wrote in message
news:RoYyb.3917 27$Tr4.1147654@ attbi_s03... Thomas Wintschel wrote: "J" <ni********@gl. gl> wrote in message
news:Xn******** **************@ 130.215.36.210. ..
Hi,
I have an array:
double *array = new double[50];
Well, I have 2 actually.
double *array2 = new double[50];
Say 'array' is poulated with 'doubles'. How do I copy all of array's
values
into 'array2'?
memcpy(array2, array, 50 * sizeof(double)) ;
Hmm...whats memcpy doing in a c++ forum :-)
memcpy() is a standard C++ library function.
-Mike This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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