Regular Expression in C#

[Jianwei Sun]

Hi, guys,

I am trying to parse out the apratment number in a regular expression :

If I use

Regex regex = new
Regex(@"(?<AddressWithoutApartment>.+)(?<Apartment Seperator>\bAPT|#|UNIT\b)(?<Apartment>.+)",
RegexOptions.ExplicitCapture);

I will be able to parse out "100 main ST # C)

But if I move "#" position in regular expression, I won't be able to
parse out the same address anymore.

Regex regex = new
Regex(@"(?<AddressWithoutApartment>.+)(?<Apartment Seperator>\bAPT|UNIT\#\b)(?<Apartment>.+)",
RegexOptions.ExplicitCapture);

Any suggestion, guru.

Thanks,
JW

[Greg Bacon]

In article <eY**************@TK2MSFTNGP09.phx.gbl>,
Jianwei Sun <js***********@gmail.com> wrote:

: I am trying to parse out the apratment number in a regular expression :
:
: If I use
:
: Regex regex = new
: Regex(@"[...](?<ApartmentSeperator>\bAPT|#|UNIT\b)[...]",
: RegexOptions.ExplicitCapture);
:
: I will be able to parse out "100 main ST # C)
:
: But if I move "#" position in regular expression, I won't be able to
: parse out the same address anymore.
:
: Regex regex = new
: Regex(@"[...](?<ApartmentSeperator>\bAPT|UNIT\#\b)[...]",
: RegexOptions.ExplicitCapture);

The latter fails to match because there's no word boundary (\b) between
an octothorpe and a space. Remember, a word boundard occurs between a
\w and a \W or vice versa, but '#' and ' ' both match \W.

A start in the right direction is (line breaks inserted):

(?<AddressWithoutApartment>.+)
(?<ApartmentSeparator>\b(APT|UNIT)\b|#(?=\s+))
(?<Apartment>.+)

Hope this helps,
Greg

[Jianwei Sun]

Greg Bacon wrote:

In article <eY**************@TK2MSFTNGP09.phx.gbl>,
Jianwei Sun <js***********@gmail.com> wrote:

: I am trying to parse out the apratment number in a regular expression :
:
: If I use
:
: Regex regex = new
: Regex(@"[...](?<ApartmentSeperator>\bAPT|#|UNIT\b)[...]",
: RegexOptions.ExplicitCapture);
:
: I will be able to parse out "100 main ST # C)
:
: But if I move "#" position in regular expression, I won't be able to
: parse out the same address anymore.
:
: Regex regex = new
: Regex(@"[...](?<ApartmentSeperator>\bAPT|UNIT\#\b)[...]",
: RegexOptions.ExplicitCapture);

The latter fails to match because there's no word boundary (\b) between
an octothorpe and a space. Remember, a word boundard occurs between a
\w and a \W or vice versa, but '#' and ' ' both match \W.

A start in the right direction is (line breaks inserted):

(?<AddressWithoutApartment>.+)
(?<ApartmentSeparator>\b(APT|UNIT)\b|#(?=\s+))
(?<Apartment>.+)

Hope this helps,
Greg

Thanks, Greg!

[Greg Bacon]

In article <#p**************@TK2MSFTNGP12.phx.gbl>,
Jianwei Sun <js***********@gmail.com> wrote:

: Thanks, Greg!

You're welcome. Glad to help.

Greg