Greetings,
I have created a series of objects for dealing with values at the binary
level (http//: www.visualassembler.com/binary). Each time I do anything with
them it seems I have to return a new instance of the object (look in the
operator overloads). This means it is immutable. Is there a way I can make
it a bit more, mutable? For performance reasons, of course. I've about
squeezed every ounce of performance I could and now need to focus on this
aspect.
Thanks,
Shawn 5 2816
"Shawn B." <le****@html.com> wrote in
news:eT**************@tk2msftngp13.phx.gbl: I have created a series of objects for dealing with values at the binary level (http//:www.visualassembler.com/binary). Each time I do anything with them it seems I have to return a new instance of the object (look in the operator overloads). This means it is immutable. Is there a way I can make it a bit more, mutable? For performance reasons, of course. I've about squeezed every ounce of performance I could and now need to focus on this aspect.
Maybe its a bit obvious, but why do you have to return a value at all??
For example, you have:
public ushort RotateLeft(int count)
{
if (count >= SIZE || count <= 0) {
throw new ArgumentOutOfRangeException(<snip>);
}
return (ushort)(((Value << count) | (Value >> (SIZE-count))) &
0xFFFF);
}
why not just...
public void RotateLeft(int count)
{
if (count >= SIZE || count <= 0) {
throw new ArgumentOutOfRangeException(<snip>);
}
Value = (ushort)(((Value << count) | (Value >> (SIZE-count))) &
0xFFFF);
}
-mbray
That's not the one I'm talking about. It's not an overloaded operator,
where I'm forced to return a new instance of the object. Besides, I don't
want to have to say (I already tried it this way) bin.RotateLeft(2) I want
to say (to keep it consistant with the rest of the behavior: int x =
bin.RotateLeft(2); or something.
Besides, in benchmarking 1 million iteration of each particular operation, I
find that the RotateLeft and RotateRight are twice as fast as when I use any
of the operators (35 ms for 1 million RotateLeft/Right, 70MS for 1 million
bin++, bin--, bin >>= 1, etc.).
Thanks,
Shawn
"Michael Bray" <mb*******************@SkPiAlMl.ctiusa.com> wrote in message
news:Xn******************************@207.46.248.1 6... "Shawn B." <le****@html.com> wrote in news:eT**************@tk2msftngp13.phx.gbl:
I have created a series of objects for dealing with values at the binary level (http//:www.visualassembler.com/binary). Each time I do anything with them it seems I have to return a new instance of the object (look in the operator overloads). This means it is immutable. Is there a way I can make it a bit more, mutable? For performance reasons, of course. I've about squeezed every ounce of performance I could and now need to focus on this aspect.
Maybe its a bit obvious, but why do you have to return a value at all?? For example, you have:
public ushort RotateLeft(int count) { if (count >= SIZE || count <= 0) { throw new ArgumentOutOfRangeException(<snip>); }
return (ushort)(((Value << count) | (Value >> (SIZE-count))) & 0xFFFF); }
why not just...
public void RotateLeft(int count) { if (count >= SIZE || count <= 0) { throw new ArgumentOutOfRangeException(<snip>); }
Value = (ushort)(((Value << count) | (Value >> (SIZE-count))) & 0xFFFF); }
-mbray
Hi Shawn,
I have no suggestion here. You have two choices, either keep it as is, or ditch the operators.
If you lose the operators, you'll have to have loads of method calls that changes the instance instead.
You'll lose consistency with the framework. If you suspect that oher people will be using these classes
then you'll want to keep the operators for clarity, so people will know how to use the classes.
On the other hand, you could use both. In other words, keep the operators in there and adding all the instance modifier methods,
giving users of the choice of coding in an optimized way or in a readable/manageable way.
--
Robert Jeppesen
robert.jeppesen%at%durius-dot-se
"Shawn B." <le****@html.com> wrote in message news:%2****************@tk2msftngp13.phx.gbl... That's not the one I'm talking about. It's not an overloaded operator, where I'm forced to return a new instance of the object. Besides, I don't want to have to say (I already tried it this way) bin.RotateLeft(2) I want to say (to keep it consistant with the rest of the behavior: int x = bin.RotateLeft(2); or something.
Besides, in benchmarking 1 million iteration of each particular operation, I find that the RotateLeft and RotateRight are twice as fast as when I use any of the operators (35 ms for 1 million RotateLeft/Right, 70MS for 1 million bin++, bin--, bin >>= 1, etc.).
Thanks, Shawn
"Michael Bray" <mb*******************@SkPiAlMl.ctiusa.com> wrote in message news:Xn******************************@207.46.248.1 6... "Shawn B." <le****@html.com> wrote in news:eT**************@tk2msftngp13.phx.gbl:
I have created a series of objects for dealing with values at the binary level (http//:www.visualassembler.com/binary). Each time I do anything with them it seems I have to return a new instance of the object (look in the operator overloads). This means it is immutable. Is there a way I can make it a bit more, mutable? For performance reasons, of course. I've about squeezed every ounce of performance I could and now need to focus on this aspect.
Maybe its a bit obvious, but why do you have to return a value at all?? For example, you have:
public ushort RotateLeft(int count) { if (count >= SIZE || count <= 0) { throw new ArgumentOutOfRangeException(<snip>); }
return (ushort)(((Value << count) | (Value >> (SIZE-count))) & 0xFFFF); }
why not just...
public void RotateLeft(int count) { if (count >= SIZE || count <= 0) { throw new ArgumentOutOfRangeException(<snip>); }
Value = (ushort)(((Value << count) | (Value >> (SIZE-count))) & 0xFFFF); }
-mbray
I had thought about this approach (I was doing so with the Shift operators)
but that extra jump cringes me. I shouldn't complain about 70 ms for 1
million X++'s, however, the 64-bit version of the class is 2x slower than
the others, the others are the same relative performance in every case.
I think I'll keep it as it is. I can emulate sufficiently a 500Mhz 6502 at
this rate, nothing to complain about.
Thanks,
Shawn
"Robert Jeppesen" <robert.jeppesen(#)durius.se> wrote in message
news:ua**************@TK2MSFTNGP10.phx.gbl... Hi Shawn,
I have no suggestion here. You have two choices, either keep it as is, or
ditch the operators. If you lose the operators, you'll have to have loads of method calls that
changes the instance instead. You'll lose consistency with the framework. If you suspect that oher
people will be using these classes then you'll want to keep the operators for clarity, so people will know
how to use the classes. On the other hand, you could use both. In other words, keep the operators
in there and adding all the instance modifier methods, giving users of the choice of coding in an optimized way or in a
readable/manageable way. -- Robert Jeppesen robert.jeppesen%at%durius-dot-se
"Shawn B." <le****@html.com> wrote in message
news:%2****************@tk2msftngp13.phx.gbl... That's not the one I'm talking about. It's not an overloaded operator, where I'm forced to return a new instance of the object. Besides, I
don't want to have to say (I already tried it this way) bin.RotateLeft(2) I
want to say (to keep it consistant with the rest of the behavior: int x = bin.RotateLeft(2); or something.
Besides, in benchmarking 1 million iteration of each particular
operation, I find that the RotateLeft and RotateRight are twice as fast as when I use
any of the operators (35 ms for 1 million RotateLeft/Right, 70MS for 1
million bin++, bin--, bin >>= 1, etc.).
Thanks, Shawn
"Michael Bray" <mb*******************@SkPiAlMl.ctiusa.com> wrote in
message news:Xn******************************@207.46.248.1 6... "Shawn B." <le****@html.com> wrote in news:eT**************@tk2msftngp13.phx.gbl:
> I have created a series of objects for dealing with values at the > binary level (http//:www.visualassembler.com/binary). Each time I
do > anything with them it seems I have to return a new instance of the > object (look in the operator overloads). This means it is
immutable. > Is there a way I can make it a bit more, mutable? For performance > reasons, of course. I've about squeezed every ounce of performance
I > could and now need to focus on this aspect.
Maybe its a bit obvious, but why do you have to return a value at
all?? For example, you have:
public ushort RotateLeft(int count) { if (count >= SIZE || count <= 0) { throw new ArgumentOutOfRangeException(<snip>); }
return (ushort)(((Value << count) | (Value >> (SIZE-count))) & 0xFFFF); }
why not just...
public void RotateLeft(int count) { if (count >= SIZE || count <= 0) { throw new ArgumentOutOfRangeException(<snip>); }
Value = (ushort)(((Value << count) | (Value >> (SIZE-count))) & 0xFFFF); }
-mbray
After further looking into the StringBuilder class, it appears mutable
because it is an array of chars treated in a similar manner to a linked
list. That would explain it. Not possible for me in these classes.
Thanks,
Shawn
"Shawn B." <le****@html.com> wrote in message
news:eT**************@tk2msftngp13.phx.gbl... Greetings,
I have created a series of objects for dealing with values at the binary level (http//:www.visualassembler.com/binary). Each time I do anything
with them it seems I have to return a new instance of the object (look in the operator overloads). This means it is immutable. Is there a way I can
make it a bit more, mutable? For performance reasons, of course. I've about squeezed every ounce of performance I could and now need to focus on this aspect.
Thanks, Shawn
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