ListView as list (how to fill the items)

[=?ISO-8859-1?Q?Norbert_P=FCrringer?=]

Hello,

I would like to know how to optimally fill a ListView, which is
defined as list, containing several columns?

The ListView contains several columns with a certain column name:

foreach (Field field in fields)
lvwData.Columns .Add(field.Name , 150,
HorizontalAlign ment.Left);

And now I want to add items. But now I need to set the value for a
column by its name. Something like:

ListViewItem item = new ListViewItem();
foreach (Field field in fields)
{
item[field.Name] = field.Value;
}
lvwData.Items.A dd(item);

But this is not possible because I have to distinguish between the
Item itself and its subitems.

Is there an easy way for me to add the items?

Thank you,
Norbert

[Peter Duniho]

On Sun, 05 Oct 2008 06:22:15 -0700, Norbert Pürringer
<th*******@graf fiti.netwrote:

[...]
And now I want to add items. But now I need to set the value for a
column by its name. Something like:

ListViewItem item = new ListViewItem();
foreach (Field field in fields)
{
item[field.Name] = field.Value;
}
lvwData.Items.A dd(item);

But this is not possible because I have to distinguish between the
Item itself and its subitems.

I don't understand the question. It's true that there's no indexer on the
ListViewItem, so the syntax you posted won't work. It also seems to me
that you need some way to provide per-item values for each item, whereas
the code you've posted seems to be enumerating the same "fields"
collection with which you initialized the column headers. But the
ListViewItem does have a SubItems property and you can use that to specify
data for each column in the "Details" view.

Is there an easy way for me to add the items?

Sure. Just fix the code you posted so that it's using the SubItems
collection and getting field values from an appropriate place.

Pete