Easy question about array

[Tony Johansson]

Hello!

As I have understood this it means the following. Correct me if I'm wrong.
You store type objects in the array obj and the first one is refering to
a and the second is refering to b and the third is refering to c.
You store reference types of type object in the array but all of them is
refering to value types(a,b,c)

int32 a = 0;
Byte b = 0;
int16 c = 0;
object[] obj = {a,b,c};

It's the same as saying
object o1 = a;
object o2 = b;
object o3 = c;

//Tony

[Duggi]

On 22 Sep, 17:44, "Tony Johansson" <t.johans...@lo gica.comwrote:

Hello!

As I have understood this it means the following. Correct me if I'm wrong..
You store type objects in the array obj and the first one is refering to
a and the second is refering to b and the third is refering to c.
You store reference types of type object in the array but all of them is
refering to value types(a,b,c)

int32 *a = 0;
Byte *b = 0;
int16 *c = 0;
object[] obj = {a,b,c};

It's the same as saying
object o1 = a;
object o2 = b;
object o3 = c;

//Tony

Array is a reference type, which holds a series of reference objects
or value type objects.

to know more http://msdn.microsoft.com/en-us/libr...53(VS.71).aspx

-Cnu

[=?ISO-8859-1?Q?G=F6ran_Andersson?=]

Tony Johansson wrote:

Hello!

As I have understood this it means the following. Correct me if I'm wrong.
You store type objects in the array obj and the first one is refering to
a and the second is refering to b and the third is refering to c.
You store reference types of type object in the array but all of them is
refering to value types(a,b,c)

int32 a = 0;
Byte b = 0;
int16 c = 0;
object[] obj = {a,b,c};

It's the same as saying
object o1 = a;
object o2 = b;
object o3 = c;

//Tony

Yes, that is correct.

To store the values in the array, each value is boxed inside an object
that is allocated on the heap.

--
Göran Andersson
_____
http://www.guffa.com