Dividing sbyte typed variables

[K Viltersten]

I try the following.

sbyte HalvOfFour () {
sbyte b = 4;
return b / 2;
}

Apparently, since 2 is regarded as int, the operation
upgrades my b to and int and after it has been
performed, i stand there with an int, which is wrong
type to return.

What i've done about it was to cast the division to a
string by adding an empty string, then parsing it
using the default parser SByte.parse (string).

It works but it sure looks ugly. Any hints?

--
Regards
Konrad Viltersten

[Paul E Collins]

"K Viltersten" <tm**@vilterste n.comwrote:

What i've done about it was to cast the division to a string by adding an
empty string, then parsing it using the default parser SByte.parse
(string).

Oof. Don't do that. Try casting the result: (sbyte) (b / 2)

Eq.

[K Viltersten]

Den 2008-06-04 12:09:19 skrev Paul E Collins
<fi************ ******@CL4.org> :

"K Viltersten" <tm**@vilterste n.comwrote:

>What i've done about it was to cast the division to a string by adding
an
empty string, then parsing it using the default parser SByte.parse
(string).

Oof. Don't do that. Try casting the result: (sbyte) (b / 2)

Ah, yes. I forgot the parenteses and type casted only b,
i'm guessing. Thanks!

--
Regards
Konrad Viltersten