Adding a form to a C# program.

[Jonny Relentless]

After adding a form to a C# program, I am unable to use it. I want to
use form1 as a sort of menu, so that when the user clicks a button,
form1 will close and form2 (or form3, etc) will open. What code must I
write to make this happen? I am new to programming, so go easy on me
with the explanation please.
Thank you for any help you can offer.

[Alberto Poblacion]

"Jonny Relentless" <Jo************ *@gmail.comwrot e in message
news:7d******** *************** ***********@x30 g2000hsd.google groups.com...

After adding a form to a C# program, I am unable to use it. I want to
use form1 as a sort of menu, so that when the user clicks a button,
form1 will close and form2 (or form3, etc) will open. What code must I
write to make this happen? I am new to programming, so go easy on me
with the explanation please.
Thank you for any help you can offer.

Add a Button to Form1. Double-click the button to open its "click" event
handler in the code-behind. Enter the following:

Form2 frm = new Form2();
frm.Show();
this.Close();

The first instruction creates an instance of the form2. The second
instruction shows it on screen (in a non-modal way, so your code continues
executing the next line). The third instruction closes the form that is
currently executing, which is the Form1 that contains the button.

Do the same with additional buttons and additional forms. As you continue to
learn, you will find that there are ways to simplify this, so that a single
"click" handler can be used for multiple buttons, but you don't need to do
this if you are just starting to experiment.

[Jonny Relentless]

On Feb 27, 12:25*pm, "Alberto Poblacion" <earthling-
quitaestoparaco ntes...@poblaci on.orgwrote:

"Jonny Relentless" <JonnyRelentl.. [e-mail] e in message

news:7d******** *************** ***********@x30 g2000hsd.google groups.com...

After adding a form to a C# program, I am unable to use it. I want to
use form1 as a sort of menu, so that when the user clicks a button,
form1 will close and form2 (or form3, etc) will open. What code must I
write to make this happen? I am new to programming, so go easy on me
with the explanation please.
Thank you for any help you can offer.

Add a Button to Form1. Double-click the button to open its "click" event
handler in the code-behind. Enter the following:

Form2 frm = new Form2();
frm.Show();
this.Close();

The first instruction creates an instance of the form2. The second
instruction shows it on screen (in a non-modal way, so your code continues
executing the next line). The third instruction closes the form that is
currently executing, which is the Form1 that contains the button.

Do the same with additional buttons and additional forms. As you continue to
learn, you will find that there are ways to simplify this, so that a single
"click" handler can be used for multiple buttons, but you don't need to do
this if you are just starting to experiment.

Thanks! That seems to be working, except that as soon as I click the
button, form2 opens and then immediately closes, ending the debugging
session. Do you know why? I added a button to form2 (trying to make it
go back to form1), but it doesn't wait for input from the user, it
just closes.

[Matt]

On Feb 27, 12:21*pm, Jonny Relentless <JonnyRelentl.. [e-mail]>
wrote:

On Feb 27, 12:25*pm, "Alberto Poblacion" <earthling-

quitaestoparaco ntes...@poblaci on.orgwrote:

"Jonny Relentless" <JonnyRelentl.. [e-mail] e in message

news:7d******** *************** ***********@x30 g2000hsd.google groups.com...

After adding a form to a C# program, I am unable to use it. I want to
use form1 as a sort of menu, so that when the user clicks a button,
form1 will close and form2 (or form3, etc) will open. What code must I
write to make this happen? I am new to programming, so go easy on me
with the explanation please.
Thank you for any help you can offer.

Add a Button to Form1. Double-click the button to open its "click" event
handler in the code-behind. Enter the following:

Form2 frm = new Form2();
frm.Show();
this.Close();

The first instruction creates an instance of the form2. The second
instruction shows it on screen (in a non-modal way, so your code continues
executing the next line). The third instruction closes the form that is
currently executing, which is the Form1 that contains the button.

Do the same with additional buttons and additional forms. As you continue to
learn, you will find that there are ways to simplify this, so that a single
"click" handler can be used for multiple buttons, but you don't need to do
this if you are just starting to experiment.

Thanks! That seems to be working, except that as soon as I click the
button, form2 opens and then immediately closes, ending the debugging
session. Do you know why? I added a button to form2 (trying to make it
go back to form1), but it doesn't wait for input from the user, it
just closes.

If you open the program.cs file for your project you will see
something like this:

Application.Ena bleVisualStyles ();
Application.Set CompatibleTextR enderingDefault (false);
Application.Run (new Form1());

The new Form1() terminates the program when the form is closed. Thus,
you can't
"close" form1, but you can hide it.

Matt

[Alberto Poblacion]

"Jonny Relentless" <Jo************ *@gmail.comwrot e in message
news:1b******** *************** ***********@c33 g2000hsd.google groups.com...

Thanks! That seems to be working, except that as soon as I click the
button, form2 opens and then immediately closes, ending the debugging
session. Do you know why?

I suspect that Form1 is the first form that you open in your program, and
you are opening it the "default" way, which is
Application.Run (new Form1());
(this code is automatically generated for you inside Program.cs).

When you start the form like that, the application terminates when you
close Form1. Since you are closing it after showing Form2, that is why Form2
is closing.
There are two possible solutions:
(1) Hide Form1 instead of Closing it (just change this.Close() into
this.Hide()).
or (2) Modify Program.cs like this:
(new Form1()).Show() ;
Applicaton.Run( );