I have the following words, and I want to extract the first part and the
trailing numbers.
OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null
I have the following regular express:
(?<first>.*?)(? <second>\d+)
This one works well for the given first two examples but not the third one.
And (?<first>.*?)(? <second>\d+)$ returns strange result.
5  2002 
I'm unfamiliar with the <first<secondsy ntax you're using, but the
following regular expression works for the three samples given:
Regex.Replace(" OP001", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "OP, 001"
Regex.Replace(" ST02", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "CD, 02"
Regex.Replace(" 00A", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussio ns.microsoft.co mwrote in message
news:FC******** *************** ***********@mic rosoft.com...
>I have the following words, and I want to extract the first part and the
trailing numbers.
OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null
I have the following regular express:
(?<first>.*?)(? <second>\d+)
This one works well for the given first two examples but not the third
one.
And (?<first>.*?)(? <second>\d+)$ returns strange result.
I am using match.Groups.
"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsy ntax you're using, but the
following regular expression works for the three samples given:
Regex.Replace(" OP001", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "OP, 001"
Regex.Replace(" ST02", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "CD, 02"
Regex.Replace(" 00A", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussio ns.microsoft.co mwrote in message
news:FC******** *************** ***********@mic rosoft.com...
I have the following words, and I want to extract the first part and the
trailing numbers.
OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null
I have the following regular express:
(?<first>.*?)(? <second>\d+)
This one works well for the given first two examples but not the third
one.
And (?<first>.*?)(? <second>\d+)$ returns strange result.
Yes, it works. Thanks.
However, there is another match, for a number
123 =123, null
how to add this one to the regular express?
"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsy ntax you're using, but the
following regular expression works for the three samples given:
Regex.Replace(" OP001", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "OP, 001"
Regex.Replace(" ST02", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "CD, 02"
Regex.Replace(" 00A", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussio ns.microsoft.co mwrote in message
news:FC******** *************** ***********@mic rosoft.com...
I have the following words, and I want to extract the first part and the
trailing numbers.
OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null
I have the following regular express:
(?<first>.*?)(? <second>\d+)
This one works well for the given first two examples but not the third
one.
And (?<first>.*?)(? <second>\d+)$ returns strange result.
Sorry, should be
123 =null, 123
"Matt" wrote:
Yes, it works. Thanks.
However, there is another match, for a number
123 =123, null
how to add this one to the regular express?
"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsy ntax you're using, but the
following regular expression works for the three samples given:
Regex.Replace(" OP001", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "OP, 001"
Regex.Replace(" ST02", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "CD, 02"
Regex.Replace(" 00A", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussio ns.microsoft.co mwrote in message
news:FC******** *************** ***********@mic rosoft.com...
>I have the following words, and I want to extract the first part and the
trailing numbers.
>
OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null
>
I have the following regular express:
(?<first>.*?)(? <second>\d+)
This one works well for the given first two examples but not the third
one.
>
And (?<first>.*?)(? <second>\d+)$ returns strange result.
>
Try something like this (not tested):
(.*\D+)?(\d*)
"Matt" <Ma**@discussio ns.microsoft.co mwrote in message
news:AB******** *************** ***********@mic rosoft.com...
Sorry, should be
123 =null, 123
"Matt" wrote:
>Yes, it works. Thanks.
However, there is another match, for a number
123 =123, null
how to add this one to the regular express?
"Brandon Gano" wrote:
I'm unfamiliar with the <first<secondsy ntax you're using, but the
following regular expression works for the three samples given:
Regex.Replace(" OP001", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "OP,
001"
Regex.Replace(" ST02", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "CD, 02"
Regex.Replace(" 00A", @"(.*\D+)(\d*)" , @"$1, $2"); // Returns: "00A, "
"Matt" <Ma**@discussio ns.microsoft.co mwrote in message
news:FC******** *************** ***********@mic rosoft.com...
I have the following words, and I want to extract the first part and
the
trailing numbers.
OP001 =ABC, 001
ST02 =CD, 02
00A =00A, null
I have the following regular express:
(?<first>.*?)(? <second>\d+)
This one works well for the given first two examples but not the
third
one.
And (?<first>.*?)(? <second>\d+)$ returns strange result.
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