Serialize Buffer Length

[Andrew Robinson]

I am using the folllowing code to serialize a [serializable] object to a
byte array (byte[]). It works fine, but my resulting array is size is being
rounded up to the next largest 32768 boundary. How can I complete the
serialization without incurring the extra bytes.

I know there is a simple answer....
Thanks,
MemoryStream memoryStream = new MemoryStream();
BinaryFormatter binaryFormatter = new BinaryFormatter ();
binaryFormatter .Serialize(memo ryStream, myObject);
byte[] b = memoryStream.Ge tBuffer();

[Andrew Robinson]

Ok, there must be a better way than this:

MemoryStream memoryStream = new MemoryStream();
BinaryFormatter binaryFormatter = new BinaryFormatter ();
binaryFormatter .Serialize(memo ryStream, myObject);
b = new byte[memoryStream.Le ngth];
Array.Copy(memo ryStream.GetBuf fer(), b, memoryStream.Le ngth);

thanks,
"Andrew Robinson" <ne****@nospam. nospamwrote in message
news:%2******** ********@TK2MSF TNGP03.phx.gbl. ..

>I am using the folllowing code to serialize a [serializable] object to a
byte array (byte[]). It works fine, but my resulting array is size is being
rounded up to the next largest 32768 boundary. How can I complete the
serializatio n without incurring the extra bytes.

I know there is a simple answer....
Thanks,
MemoryStream memoryStream = new MemoryStream();
BinaryFormatter binaryFormatter = new BinaryFormatter ();
binaryFormatter .Serialize(memo ryStream, myObject);
byte[] b = memoryStream.Ge tBuffer();

[Andrew Robinson]

Ok, I think I have answered my own question here:
using (MemoryStream memoryStream = new MemoryStream()) {
BinaryFormatter binaryFormatter = new BinaryFormatter ();
binaryFormatter .Serialize(memo ryStream, myObject);
b = memoryStream.To Array();
memoryStream.Cl ose();
}

"Andrew Robinson" <ne****@nospam. nospamwrote in message
news:ua******** ******@TK2MSFTN GP02.phx.gbl...

Ok, there must be a better way than this:

MemoryStream memoryStream = new MemoryStream();
BinaryFormatter binaryFormatter = new BinaryFormatter ();
binaryFormatter .Serialize(memo ryStream, myObject);
b = new byte[memoryStream.Le ngth];
Array.Copy(memo ryStream.GetBuf fer(), b, memoryStream.Le ngth);

thanks,
"Andrew Robinson" <ne****@nospam. nospamwrote in message
news:%2******** ********@TK2MSF TNGP03.phx.gbl. ..

>>I am using the folllowing code to serialize a [serializable] object to a
byte array (byte[]). It works fine, but my resulting array is size is
being rounded up to the next largest 32768 boundary. How can I complete
the serialization without incurring the extra bytes.

I know there is a simple answer....
Thanks,
MemoryStream memoryStream = new MemoryStream();
BinaryFormatte r binaryFormatter = new BinaryFormatter ();
binaryFormatte r.Serialize(mem oryStream, myObject);
byte[] b = memoryStream.Ge tBuffer();

[Jon Skeet [C# MVP]]

Andrew Robinson <ne****@nospam. nospamwrote:

Ok, I think I have answered my own question here:
using (MemoryStream memoryStream = new MemoryStream()) {
BinaryFormatter binaryFormatter = new BinaryFormatter ();
binaryFormatter .Serialize(memo ryStream, myObject);
b = memoryStream.To Array();
memoryStream.Cl ose();
}

Exactly. Note that you don't need to call Close() - you're using a
"using" statement which will call Dispose on your MemoryStream already.

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
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