Hello,
I want to iterate the second dimension of a 2-dim-array.
Let´s say I have an array:
double[,] myArray and a given index: int i.
Assume my index is given in want to iterate my array with something like
this:
int i = 2;
double sum= 0.0;
for(int j = 0; j < myArray[i].Length; j++)
sum += myArray[i,j];
But this does not work, because I am using the 2dim-array as 1dim-array.
My problem is... how do i get the size of the second dimension?
Regards,
Martin 5 2690
Martin Pöpping wrote:
Hello,
I want to iterate the second dimension of a 2-dim-array.
Let´s say I have an array:
double[,] myArray and a given index: int i.
Assume my index is given in want to iterate my array with something like
this:
int i = 2;
double sum= 0.0;
for(int j = 0; j < myArray[i].Length; j++)
sum += myArray[i,j];
But this does not work, because I am using the 2dim-array as 1dim-array.
My problem is... how do i get the size of the second dimension?
Regards,
Martin
double[,] a=new double[10,10];
for(int i=0;i<10;i++)
{
for(int j=0;j<10;j++)
{
a[i,j]=i*j;
}
}
//or try
foreach(double d in a)
{
Console.WriteLi ne(d.ToString() );
}
DeveloperX schrieb:
double[,] a=new double[10,10];
for(int i=0;i<10;i++)
{
for(int j=0;j<10;j++)
{
a[i,j]=i*j;
}
}
Well maybe you missunderstand my problem.
I do not know the second dimension.
In your example.... I do not know that j = 10.
//or try
foreach(double d in a)
{
Console.WriteLi ne(d.ToString() );
}
If it would work... it would traverse the whole dimensional array.
I only want to work on a[2,j] for example.
Regards,
Martin
Martin P?pping <ma******@despa mmed.comwrote:
I want to iterate the second dimension of a 2-dim-array.
Let?s say I have an array:
double[,] myArray and a given index: int i.
Assume my index is given in want to iterate my array with something like
this:
int i = 2;
double sum= 0.0;
for(int j = 0; j < myArray[i].Length; j++)
sum += myArray[i,j];
But this does not work, because I am using the 2dim-array as 1dim-array.
My problem is... how do i get the size of the second dimension?
Use Array.GetLength (int dimension)
--
Jon Skeet - <sk***@pobox.co m> http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too
Martin,
If you don't know anything about the array then you need to use the Array
class method and properties. Array is a base class for all arrays and as
such all arrays have them.
Check MSDN docs. Here are some usefull methods and proeprties that you may
want to use:
- Length (property) - total number of elements in all dimensions
- Rank (property) - number of dimensions
- GetLength (method) - return number of element is a specified dimension.
--
HTH
Stoitcho Goutsev (100)
"Martin Pöpping" <ma******@despa mmed.comwrote in message
news:ef******** **@newsreader2. netcologne.de.. .
DeveloperX schrieb:
>double[,] a=new double[10,10];
for(int i=0;i<10;i++) { for(int j=0;j<10;j++) { a[i,j]=i*j; } }
Well maybe you missunderstand my problem.
I do not know the second dimension.
In your example.... I do not know that j = 10.
>//or try foreach(doub le d in a) { Console.WriteL ine(d.ToString( )); }
If it would work... it would traverse the whole dimensional array.
I only want to work on a[2,j] for example.
Regards,
Martin
In addition there is
GetUpperBound(d imension), returning the last index (length - 1)
On Tue, 26 Sep 2006 16:04:32 +0200, Stoitcho Goutsev (100) <10*@100.com>
wrote:
Martin,
If you don't know anything about the array then you need to use the Array
class method and properties. Array is a base class for all arrays and as
such all arrays have them.
Check MSDN docs. Here are some usefull methods and proeprties that you
may
want to use:
- Length (property) - total number of elements in all dimensions
- Rank (property) - number of dimensions
- GetLength (method) - return number of element is a specified dimension.
--
Happy Coding!
Morten Wennevik [C# MVP] This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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