How to get the same as MS FCIV

[andrewcw]

I have a VB 5 program that computes an MD5HASH on a file.
I can get the same number using Microsoft FCIV.

But this code does not. ( What more should I do to get the file's hash as
the legacy and MS FCIV tool ??

In my attempts at code I get the file length and then convert that to a
string which I pass to 2 methods to create a hash - each off the net, but
they are different and not the desired hash value.

public string getFileHash(str ing filePath)
{
string retVal = "";
// open file
try
{
FileInfo fi = new FileInfo(filePa th);
long fileLength = fi.Length;
string fileString = Convert.ToStrin g(fileLength);
retVal = Md5Hash(fileStr ing); // method 1
string retVal2 = Md5Hash2(fileSt ring); // method 2
retVal = retVal + " : " + retVal2;
}
catch (Exception e)
{
Console.WriteLi ne(e.Message);
retVal = "";
}
return retVal;

}

public static string Md5Hash(string pass)
{
MD5 md5 = MD5CryptoServic eProvider.Creat e();
byte[] dataMd5 = md5.ComputeHash (Encoding.Defau lt.GetBytes(pas s));
StringBuilder sb = new StringBuilder() ;
for (int i = 0; i < dataMd5.Length; i++)
sb.AppendFormat ("{0:x2}", dataMd5[i]);
return sb.ToString();

}
public static string Md5Hash2(string str)
{

// Create a buffer large enough to hold the string
byte[] unicodeText = new byte[str.Length * 2];
Encoder enc = System.Text.Enc oding.Unicode.G etEncoder();
// Now that we have a byte array we can ask the CSP to hash it
MD5 md5 = new MD5CryptoServic eProvider();
byte[] result = md5.ComputeHash (unicodeText);

// Build the final string by converting each byte
// into hex and appending it to a StringBuilder
StringBuilder sb = new StringBuilder() ;
for (int i = 0; i < result.Length; i++)
{
sb.Append(resul t[i].ToString("X2") );
}

// And return it
return sb.ToString();

}
--
Andrew

[andrewcw]

OK finally solved it :

This works for binary files:

public string getFileHashBina ry(string filePath)
{
string retVal = "";
try
{ // this works for binary files
FileInfo fi = new FileInfo(filePa th);
long fileLength = fi.Length;
MD5 md5 = MD5CryptoServic eProvider.Creat e();
FileStream fs = new FileStream(file Path, FileMode.Open);
Byte[] bBuffer = new byte[fileLength];
int something= fs.Read(bBuffer , 0,(int)fileLeng th);
byte[] dataMd5 = md5.ComputeHash (bBuffer);
fs.Close();
StringBuilder sb = new StringBuilder() ;
for (int i = 0; i < dataMd5.Length; i++)
sb.AppendFormat ("{0:x2}", dataMd5[i]);
retVal= sb.ToString();

}
catch (Exception e)
{
Console.WriteLi ne(e.Message);
retVal = "";
}
return retVal;

}

--
Andrew
"andrewcw" wrote:

I have a VB 5 program that computes an MD5HASH on a file.
I can get the same number using Microsoft FCIV.

But this code does not. ( What more should I do to get the file's hash as
the legacy and MS FCIV tool ??

In my attempts at code I get the file length and then convert that to a
string which I pass to 2 methods to create a hash - each off the net, but
they are different and not the desired hash value.

public string getFileHash(str ing filePath)
{
string retVal = "";
// open file
try
{
FileInfo fi = new FileInfo(filePa th);
long fileLength = fi.Length;
string fileString = Convert.ToStrin g(fileLength);
retVal = Md5Hash(fileStr ing); // method 1
string retVal2 = Md5Hash2(fileSt ring); // method 2
retVal = retVal + " : " + retVal2;
}
catch (Exception e)
{
Console.WriteLi ne(e.Message);
retVal = "";
}
return retVal;

}

public static string Md5Hash(string pass)
{
MD5 md5 = MD5CryptoServic eProvider.Creat e();
byte[] dataMd5 = md5.ComputeHash (Encoding.Defau lt.GetBytes(pas s));
StringBuilder sb = new StringBuilder() ;
for (int i = 0; i < dataMd5.Length; i++)
sb.AppendFormat ("{0:x2}", dataMd5[i]);
return sb.ToString();

}
public static string Md5Hash2(string str)
{

// Create a buffer large enough to hold the string
byte[] unicodeText = new byte[str.Length * 2];
Encoder enc = System.Text.Enc oding.Unicode.G etEncoder();
// Now that we have a byte array we can ask the CSP to hash it
MD5 md5 = new MD5CryptoServic eProvider();
byte[] result = md5.ComputeHash (unicodeText);

// Build the final string by converting each byte
// into hex and appending it to a StringBuilder
StringBuilder sb = new StringBuilder() ;
for (int i = 0; i < result.Length; i++)
{
sb.Append(resul t[i].ToString("X2") );
}

// And return it
return sb.ToString();

}
--
Andrew

[Tom Spink]

andrewcw wrote:

OK finally solved it :

This works for binary files:

public string getFileHashBina ry(string filePath)
{
string retVal = "";
try
{ // this works for binary files
FileInfo fi = new FileInfo(filePa th);
long fileLength = fi.Length;
MD5 md5 = MD5CryptoServic eProvider.Creat e();
FileStream fs = new FileStream(file Path, FileMode.Open);
Byte[] bBuffer = new byte[fileLength];
int something= fs.Read(bBuffer , 0,(int)fileLeng th);
byte[] dataMd5 = md5.ComputeHash (bBuffer);
fs.Close();
StringBuilder sb = new StringBuilder() ;
for (int i = 0; i < dataMd5.Length; i++)
sb.AppendFormat ("{0:x2}", dataMd5[i]);
retVal= sb.ToString();

}
catch (Exception e)
{
Console.WriteLi ne(e.Message);
retVal = "";
}
return retVal;

}

Hi Andrew,

You could actually stream-line it, if you wanted:

public string GetFileHashBina ry ( string filePath )
{
StringBuilder retVal = new StringBuilder() ;

try
{
MD5 md5 = MD5.Create();

byte[] fileHash;
using ( FileStream fs = File.OpenRead( filePath ) )
fileHash = md5.ComputeHash ( fs );

foreach ( byte b in fileHash )
retVal.AppendFo rmat( "{0:x2}", b );
}
catch ( Exception e )
{
Console.WriteLi ne( e.Message );
return string.Empty;
}

return retVal.ToString ();
}

--
-- Tom Spink

[andrewcw]

Yes that is much cleaner - thank you !
--
Andrew
"Tom Spink" wrote:

andrewcw wrote:

OK finally solved it :

This works for binary files:

public string getFileHashBina ry(string filePath)
{
string retVal = "";
try
{ // this works for binary files
FileInfo fi = new FileInfo(filePa th);
long fileLength = fi.Length;
MD5 md5 = MD5CryptoServic eProvider.Creat e();
FileStream fs = new FileStream(file Path, FileMode.Open);
Byte[] bBuffer = new byte[fileLength];
int something= fs.Read(bBuffer , 0,(int)fileLeng th);
byte[] dataMd5 = md5.ComputeHash (bBuffer);
fs.Close();
StringBuilder sb = new StringBuilder() ;
for (int i = 0; i < dataMd5.Length; i++)
sb.AppendFormat ("{0:x2}", dataMd5[i]);
retVal= sb.ToString();

}
catch (Exception e)
{
Console.WriteLi ne(e.Message);
retVal = "";
}
return retVal;

}

Hi Andrew,

You could actually stream-line it, if you wanted:

public string GetFileHashBina ry ( string filePath )
{
StringBuilder retVal = new StringBuilder() ;

try
{
MD5 md5 = MD5.Create();

byte[] fileHash;
using ( FileStream fs = File.OpenRead( filePath ) )
fileHash = md5.ComputeHash ( fs );

foreach ( byte b in fileHash )
retVal.AppendFo rmat( "{0:x2}", b );
}
catch ( Exception e )
{
Console.WriteLi ne( e.Message );
return string.Empty;
}

return retVal.ToString ();
}

--
-- Tom Spink