How to get a part of a string using reg exp

[Mike9900]

I need to get 00021 in "00sddsd00021ds d" and then increment it to become
"00sddsd00022ds d". Is there a way?
--
Mike

[Daniel]

Yep.

Get the substring, parse it to an int, increment it, then turn it back into
a string and put it back in.

Havent compiled this but this should work:

string s = "00sddsd00021ds d";

string theNum = s.Substring(7, 5);

int intNum = int.Parse(theNu m);

intNum++;

string finalString = s.Replace(theNu m, intNum.ToString ());
"Mike9900" <Mi******@discu ssions.microsof t.com> wrote in message
news:C4******** *************** ***********@mic rosoft.com...

I need to get 00021 in "00sddsd00021ds d" and then increment it to become
"00sddsd00022ds d". Is there a way?
--
Mike

[Daniel]

Let me know if it does work by the way Mike, did it in about 1 min so
fingers crossed.
"Mike9900" <Mi******@discu ssions.microsof t.com> wrote in message
news:C4******** *************** ***********@mic rosoft.com...

I need to get 00021 in "00sddsd00021ds d" and then increment it to become
"00sddsd00022ds d". Is there a way?
--
Mike

[Göran Andersson]

That turns the string from "00sddsd00021ds d" to "00sddsd22d sd". You have
to specify the format when you turn the incremented value back into a
string.

Daniel wrote:

Yep.

Get the substring, parse it to an int, increment it, then turn it back into
a string and put it back in.

Havent compiled this but this should work:

string s = "00sddsd00021ds d";

string theNum = s.Substring(7, 5);

int intNum = int.Parse(theNu m);

intNum++;

string finalString = s.Replace(theNu m, intNum.ToString ());
"Mike9900" <Mi******@discu ssions.microsof t.com> wrote in message
news:C4******** *************** ***********@mic rosoft.com...

I need to get 00021 in "00sddsd00021ds d" and then increment it to become
"00sddsd00022ds d". Is there a way?
--
Mike

[Daniel]

lol oops, as i say , did make the code in 1min and yep you would......geez
give me a break lol

"Göran Andersson" <gu***@guffa.co m> wrote in message
news:eX******** ******@TK2MSFTN GP03.phx.gbl...

That turns the string from "00sddsd00021ds d" to "00sddsd22d sd". You have
to specify the format when you turn the incremented value back into a
string.

Daniel wrote:

Yep.

Get the substring, parse it to an int, increment it, then turn it back
into a string and put it back in.

Havent compiled this but this should work:

string s = "00sddsd00021ds d";

string theNum = s.Substring(7, 5);

int intNum = int.Parse(theNu m);

intNum++;

string finalString = s.Replace(theNu m, intNum.ToString ());
"Mike9900" <Mi******@discu ssions.microsof t.com> wrote in message
news:C4******** *************** ***********@mic rosoft.com...

I need to get 00021 in "00sddsd00021ds d" and then increment it to become
"00sddsd00022ds d". Is there a way?
--
Mike

[Mike9900]

It sounds nice, thanks.

But we do not know the length of the string, nor we know the format. We
only want to increment the number embeded inside the string. The string
could be like
"00vv00fg00021d sd", and so we want to produce "00vv00fg00022d sd.
--
Mike
"Daniel" wrote:

Yep.

Get the substring, parse it to an int, increment it, then turn it back into
a string and put it back in.

Havent compiled this but this should work:

string s = "00sddsd00021ds d";

string theNum = s.Substring(7, 5);

int intNum = int.Parse(theNu m);

intNum++;

string finalString = s.Replace(theNu m, intNum.ToString ());
"Mike9900" <Mi******@discu ssions.microsof t.com> wrote in message
news:C4******** *************** ***********@mic rosoft.com...

I need to get 00021 in "00sddsd00021ds d" and then increment it to become
"00sddsd00022ds d". Is there a way?
--
Mike

[Göran Andersson]

That string contains three numbers. How do you know which one should be
incremented?

Mike9900 wrote:

It sounds nice, thanks.

But we do not know the length of the string, nor we know the format. We
only want to increment the number embeded inside the string. The string
could be like
"00vv00fg00021d sd", and so we want to produce "00vv00fg00022d sd.

[Marcus Andrén]

On Wed, 14 Jun 2006 13:22:02 -0700, Mike9900
<Mi******@discu ssions.microsof t.com> wrote:

It sounds nice, thanks.

But we do not know the length of the string, nor we know the format. We
only want to increment the number embeded inside the string. The string
could be like
"00vv00fg00021 dsd", and so we want to produce "00vv00fg00022d sd.

You have been a little vague, so I can only give an on what you have
given.

Assuming it is is a five digit number and it is the only five digit
number in the string, this should work.

string input = "00vd00asd00999 asdkk";

Match m = Regex.Match(inp ut,@"(.*)(\d{5} )(.*)");

int val = Convert.ToInt32 (m.Groups[2].Value);
val++;

string result = m.Groups[1].Value +
val.ToString("0 0000") +
m.Groups[3].Value;

Console.WriteLi ne(result);

--
Marcus Andrén

[Jesse Houwing]

Marcus Andrén wrote:

On Wed, 14 Jun 2006 13:22:02 -0700, Mike9900
<Mi******@discu ssions.microsof t.com> wrote:

It sounds nice, thanks.

But we do not know the length of the string, nor we know the format. We
only want to increment the number embeded inside the string. The string
could be like
"00vv00fg00021d sd", and so we want to produce "00vv00fg00022d sd.

You have been a little vague, so I can only give an on what you have
given.

Assuming it is is a five digit number and it is the only five digit
number in the string, this should work.

string input = "00vd00asd00999 asdkk";

Match m = Regex.Match(inp ut,@"(.*)(\d{5} )(.*)");

int val = Convert.ToInt32 (m.Groups[2].Value);
val++;

string result = m.Groups[1].Value +
val.ToString("0 0000") +
m.Groups[3].Value;

Console.WriteLi ne(result);

You can rewrite this using a MatchEvaluator to make it a little easier
(and faster):

Regex rx = new Regex(@"\d+");
string s = "00vv00fg00021d sd";
s = rx.Replace(s, new MatchEvaluator( this.Increment) );
public string Increment(Match m)
{
int i = int.Parse(m.Val ue);
i++;
return i.ToString().Pa dLeft(m.Value.L ength, '0') ;
}

This also increments the other two 00 numbers though, but it wouldn't be
too hard to exclude those. Using the following MatchEvaluator instead
would skip any number that is equal to 0.

public string Increment(Match m)
{
int i = int.Parse(m.Val ue);
if (i > 0) { i++; }
return i.ToString().Pa dLeft(m.Value.L ength, '0') ;
}

Jesse Houwing