DateTime manipulation

[Patrick B]

Say I have three DateTime variables:

DateTime A;
DateTime B;
DateTime C;

How can I assign to C just the date part of A and just the time part of B?

Something like this...

C = A.Date + B.TimeOfDay;

Except that isn't it.

[Jon Skeet [C# MVP]]

Patrick B <ne*******@devz oo.com> wrote:

Say I have three DateTime variables:

DateTime A;
DateTime B;
DateTime C;

How can I assign to C just the date part of A and just the time part of B?

Something like this...

C = A.Date + B.TimeOfDay;

Except that isn't it.

I ended up writing a utility method which did something like this -
it's not hard to write once and then use repeatedly. Basically use the
form of the DateTime constructor which takes everything you want, and
take some parts from A and some parts from B.

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

[Ignacio Machin \( .NET/ C# MVP \)]

Hi,

Another solution could be take the data part of A

a.Date

and the time components of B

b.Second , b.Hour , b.Minute

That should work

Cheers,

--
Ignacio Machin,
ignacio.machin AT dot.state.fl.us
Florida Department Of Transportation

"Jon Skeet [C# MVP]" <sk***@pobox.co m> wrote in message
news:MP******** *************** *@msnews.micros oft.com...

Patrick B <ne*******@devz oo.com> wrote:

Say I have three DateTime variables:

DateTime A;
DateTime B;
DateTime C;

How can I assign to C just the date part of A and just the time part of
B?

Something like this...

C = A.Date + B.TimeOfDay;

Except that isn't it.

I ended up writing a utility method which did something like this -
it's not hard to write once and then use repeatedly. Basically use the
form of the DateTime constructor which takes everything you want, and
take some parts from A and some parts from B.

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

[Nicholas Paldino [.NET/C# MVP]]

Or, if we wanted to be really nifty:

// Get the date and time.
DateTime now = DateTime.Now();

// Get the date portion, and the time.
DateTime date = now.Date;
TimeSpan time = now.TimeOfDay;

Hope this helps.

--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m

"Ignacio Machin ( .NET/ C# MVP )" <ignacio.mach in AT dot.state.fl.us > wrote
in message news:%2******** ********@TK2MSF TNGP12.phx.gbl. ..

Hi,

Another solution could be take the data part of A

a.Date

and the time components of B

b.Second , b.Hour , b.Minute

That should work

Cheers,

--
Ignacio Machin,
ignacio.machin AT dot.state.fl.us
Florida Department Of Transportation

"Jon Skeet [C# MVP]" <sk***@pobox.co m> wrote in message
news:MP******** *************** *@msnews.micros oft.com...

Patrick B <ne*******@devz oo.com> wrote:

Say I have three DateTime variables:

DateTime A;
DateTime B;
DateTime C;

How can I assign to C just the date part of A and just the time part of
B?

Something like this...

C = A.Date + B.TimeOfDay;

Except that isn't it.

I ended up writing a utility method which did something like this -
it's not hard to write once and then use repeatedly. Basically use the
form of the DateTime constructor which takes everything you want, and
take some parts from A and some parts from B.

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

[Patrick B]

Ahh, I get you...

DateTime C = new DateTime(A.Year , A.Month, A.Day, B.Hour, B.Minute,
B.Second);

Thanks, that works.

[Anders Norås [MCAD]]

Patrick B wrote:

How can I assign to C just the date part of A and just the time part of B?

Use the DateTime constructor with Year, Month and Day from DateTime a
and Hour, Minute and Second from DateTime b.

DateTime a=new DateTime(2005,0 1,04);
DateTime b=DateTime.Now;
DateTime c=new DateTime(a.Year ,a.Month,a.Day, b.Hour,b.Minute ,b.Second);

Anders Norås
http://dotnetjunkies.com/weblog/anoras/

[Jon Skeet [C# MVP]]

Patrick B <ne*******@devz oo.com> wrote:

Ahh, I get you...

DateTime C = new DateTime(A.Year , A.Month, A.Day, B.Hour, B.Minute,
B.Second);

Thanks, that works.

Goodo - but actually, looking at your original post, I don't see why
that shouldn't work. For instance:

using System;

class Test
{
static void Main()
{
DateTime now = DateTime.Now;
DateTime yesterday = DateTime.Today. AddDays(-1);
DateTime thisTimeYesterd ay = yesterday.Date+ now.TimeOfDay;

Console.WriteLi ne(thisTimeYest erday);
}
}

--
Jon Skeet - <sk***@pobox.co m>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

[Ciaran]

Try This

DateTime A = DateTime.Now;

DateTime B = DateTime.Now.Ad d(-1);

DateTime C = A.Date.AddTicks (B.TimeOfDay.Ti cks);

Ciaran

"Patrick B" <ne*******@devz oo.com> wrote in message
news:ui******** ******@TK2MSFTN GP09.phx.gbl...

Say I have three DateTime variables:

DateTime A;
DateTime B;
DateTime C;

How can I assign to C just the date part of A and just the time part of B?

Something like this...

C = A.Date + B.TimeOfDay;

Except that isn't it.