Hashtable.Clone () is shadow copy, how to depth copy hashtable?

[harvie wang]

Hi,
I want to implement a copy construct class, but the class have as Hashtable,how
to do?
public class A
{
private Hashtable _data;
public A()
{
_data = new Hashtable();
}
public A(A obj)
{
_data = A._data.Clone() ; //but this is shadow copy
}
public void func()
{
private ClassA a = new ClassA();
private ClassB b = new ClassB();
_data.Add("a",a );
_data.Add("b",b );
}
}

public main()
{
private A a;
private A b;
a.func();
private A c = new A(a); //I want to set c._data["a"] is a new
ClassA
b = a;
}
best wish,

Harvie

2005-10-27

[Daniel O'Connell [C# MVP]]

"harvie wang" <qu*****@gmail. com> wrote in message
news:5e******** *************** ***@news.micros oft.com...

Hi,
I want to implement a copy construct class, but the class have as
Hashtable,how to do?

You aren't going to be able to do it in general. The objects contained in
the hashtable are going to have to be able to clone themselves.

[harvie wang]

Hello Daniel O'Connell [C# MVP],
thanks!

Is the class A can do the copy work?
private A a = new A();
a.func();
private A b = new B();
b = a;//
now b._data have a ClassA object? have a handle of object?

ClassA a = (ClassA)b._data["a"];
ClassA b = (ClassA)a._data["a"];
AddressOf(a) isn't equal to AddressOf(b)?

"harvie wang" <qu*****@gmail. com> wrote in message
news:5e******** *************** ***@news.micros oft.com...

Hi,
I want to implement a copy construct class, but the class have as
Hashtable,how to do?

You aren't going to be able to do it in general. The objects contained
in the hashtable are going to have to be able to clone themselves.

[Daniel O'Connell [C# MVP]]

"harvie wang" <qu*****@gmail. com> wrote in message
news:5e******** *************** ***@news.micros oft.com...

Hello Daniel O'Connell [C# MVP],
thanks!

Is the class A can do the copy work?
private A a = new A();
a.func();
private A b = new B();
b = a;//
now b._data have a ClassA object? have a handle of object?
b would be a reference that a had. You will not get C++ style assignmnt
copying.

ClassA a = (ClassA)b._data["a"];
ClassA b = (ClassA)a._data["a"];
AddressOf(a) isn't equal to AddressOf(b)?

I'm not sure what you mean here.

[harvie wang]

Hi, Daniel O'Connell

Thanks very much!

ClassA a = (ClassA)b._data["a"];
ClassA b = (ClassA)a._data["a"];
AddressOf(a) isn't equal to AddressOf(b)?

I mean suppose that the memory address of object a is 0x1234, what's
the memory address of object b ? Is 0x1234?

Harvie

2005-10-28
"harvie wang" <qu*****@gmail. com> wrote in message
news:5e******** *************** ***@news.micros oft.com...

Hello Daniel O'Connell [C# MVP],
thanks!
Is the class A can do the copy work?
private A a = new A();
a.func();
private A b = new B();
b = a;//
now b._data have a ClassA object? have a handle of object?

b would be a reference that a had. You will not get C++ style
assignmnt copying.

ClassA a = (ClassA)b._data["a"];
ClassA b = (ClassA)a._data["a"];
AddressOf(a) isn't equal to AddressOf(b)?

I'm not sure what you mean here.

[harvie wang]

Hello Daniel O'Connell [C# MVP],
thanks!
copy construct can get new object, such as :
public class Test
{
private int a;
private string s;
private Hashtable h;
public Test()
{
a = 10;
s = "hello";
h = new Hashtable;
}
public Test(Test t)
{
a = t.a;
s = t.s;
h = t.h;//copy?
h = (Hashtable)t.h. Clone() // shadow copy
}
public void func()
{
ClassA testa = new ClassA();
ClassA testb = new ClassA();
h.Add("a",testa );
h.Add("b",testb );
a = 15;
}
}

void main()
{
private Test a = new Test();
a.func();
private Test b = new Test(a); //here b.h have testa and testb
and b.a = 15
//object b is a new object, I want b.h is a new Hashtable
private Test c = new Test(); // here c.h has no element and
c.a = 10
c = a; // c is a refrence ,not I want
}

"harvie wang" <qu*****@gmail. com> wrote in message
news:5e******** *************** ***@news.micros oft.com...

Hello Daniel O'Connell [C# MVP],
thanks!
Is the class A can do the copy work?
private A a = new A();
a.func();
private A b = new B();
b = a;//
now b._data have a ClassA object? have a handle of object?

b would be a reference that a had. You will not get C++ style
assignmnt copying.

ClassA a = (ClassA)b._data["a"];
ClassA b = (ClassA)a._data["a"];
AddressOf(a) isn't equal to AddressOf(b)?

I'm not sure what you mean here.

[Daniel O'Connell [C# MVP]]

"harvie wang" <qu*****@gmail. com> wrote in message
news:5e******** *************** ***@news.micros oft.com...

Hi, Daniel O'Connell

Thanks very much!

>> ClassA a = (ClassA)b._data["a"];
>> ClassA b = (ClassA)a._data["a"];
>> AddressOf(a) isn't equal to AddressOf(b)?

I mean suppose that the memory address of object a is 0x1234, what's
the memory address of object b ? Is 0x1234?

Well, that code is kinda ambigious(infac t it doesn't work), but in that case
I would guess yes, the address would be hte same. it'd be far clearer if a
and b weren't assigned from themselves.