Passing params object[] args signatured method's parameters to another -same signatured- method.

[The Crow]

code snippet below briefly shows what i need to do :

public void Method1(params object[] args)
{
Method2(args);
}

public void Method2(params object[] args)
{
//Do something.
}
in Method1 i pass all coming parameters to Method2, but i thing it will call
Method2 such a Method2(object[] args)... to be more clear, i would access
parameters in Method2 like args[0][0], args[0][1] ..... how can i prevent
this?

[Oliver Sturm]

The Crow wrote:

code snippet below briefly shows what i need to do :

public void Method1(params object[] args)
{
Method2(args);
}

public void Method2(params object[] args)
{
//Do something.
}
in Method1 i pass all coming parameters to Method2, but i thing it will
call Method2 such a Method2(object[] args)... to be more clear, i would
access parameters in Method2 like args[0][0], args[0][1] ..... how can i
prevent this?

Where do you get this idea from? Why don't you just try it?
Oliver Sturm
--
Expert programming and consulting services available
See http://www.sturmnet.org (try /blog as well)

[Christof Nordiek]

"The Crow" <q> schrieb im Newsbeitrag
news:uf******** ******@TK2MSFTN GP14.phx.gbl...

code snippet below briefly shows what i need to do :

public void Method1(params object[] args)
{
Method2(args);
}

public void Method2(params object[] args)
{
//Do something.
}
in Method1 i pass all coming parameters to Method2, but i thing it will
call Method2 such a Method2(object[] args)... to be more clear, i would
access parameters in Method2 like args[0][0], args[0][1] ..... how can i
prevent this?

Did you test it?
It should use the normal form of Method2 since it is applicable.

From the spec:
<quote>
The expanded form of a method is available only if the normal form of the
method
is not applicable and only if a method with the same signature as the
expanded form
is not already declared in the same type.
</quote>

To call the expanded form (i.e. to args of Method1 will be the one element
of args in Method2),
you'll have to call:
Method2((object )args);

Christof

[The Crow]

ive got this idea from, thinking the type of args as a normal array. but
yes, you are right i should have tried it. it worked as expected to be.
now i wonder, what is the actual type of args? a special type?
i think c# compiler do some trick behind the scenes around there. what do
you think?

[Christof Nordiek]

"The Crow" <q> schrieb im Newsbeitrag
news:%2******** ********@TK2MSF TNGP14.phx.gbl. ..

ive got this idea from, thinking the type of args as a normal array. but
yes, you are right i should have tried it. it worked as expected to be.
now i wonder, what is the actual type of args? a special type?
i think c# compiler do some trick behind the scenes around there. what do
you think?

the type of args is object[] in both cases.
the paramarray keyword only changes the way it can be called.
If the expanded form is called c# creates an array of the given type and
put's the
parameters in it.
See my other post about when the expanded form is considered by the
compiler.

[The Crow]

only public static int GetValue2(bool[] args) is called. then what is the
benefit of supplying params keyword before the paremter rather then using
bool[] args? (int this situation of course)

using System;

using System.IO;

using System.Windows. Forms;

using System.Net;

namespace ConsoleApplicat ion1

{

/// <summary>

/// Summary description for Class1.

/// </summary>

class Class1

{

/// <summary>

/// The main entry point for the application.

/// </summary>

[STAThread]

static void Main(string[] args)

{

try

{

GetValue(true, false);

}

catch(Exception ex)

{

Console.WriteLi ne(ex.Message);

}

Console.ReadLin e();

}

public static int GetValue(params bool[] args)

{

return GetValue2(args) ;

}

public static int GetValue2(bool param1, bool param2)

{

if(param1)

return 1;

else

return 0;

}

public static int GetValue2(bool[] args)

{

if(args[0])

return 1;

else

return 0;

}

}

}

[The Crow]

ok. i was always late for my other 2 posts. now everything is clear.

[Christof Nordiek]

should be params where i wrote paramarray ;-)