How to open an image file and display in picturebox?

[Bradley1234]

Seems simple but Im missing something. In a C# form Ive got a picturebox
and a button

I have the File Open dialog linked to the button, but Im drawing a blank on
how to take the stream and push the thing onto the picturebox.

Here is the code, tia

OpenFileDialog fileChooser = new OpenFileDialog( );

DialogResult result = fileChooser.Sho wDialog();

string filename; //name of file containint data

if (result == DialogResult.Ca ncel)

return;

filename = fileChooser.Fil eName;

if (filename == "" || filename == null)

MessageBox.Show ("Hey, thats a not a what I want a see", "Error",
MessageBoxButto ns.OK, MessageBoxIcon. Error);

else

{

input = new FileStream(file name, FileMode.Open, FileAccess.Read );

}

try {

pictureBox1.Ima ge = input; //NO WAY, IT HAS AN ERROR THAT SAYS

cannot implicity convert type system.io.files tream to system.drawing. image

}

catch( Exception ex )

[CiccioPalla]

Image img = Image.FromFile( filename);

pictureBox1.Ima ge = img;

"Bradley123 4" <so*****@yahoo. com> ha scritto nel messaggio
news:wjvpd.9717 $5v1.749@trnddc 06...

Seems simple but Im missing something. In a C# form Ive got a picturebox
and a button

I have the File Open dialog linked to the button, but Im drawing a blank on how to take the stream and push the thing onto the picturebox.

Here is the code, tia

OpenFileDialog fileChooser = new OpenFileDialog( );

DialogResult result = fileChooser.Sho wDialog();

string filename; //name of file containint data

if (result == DialogResult.Ca ncel)

return;

filename = fileChooser.Fil eName;

if (filename == "" || filename == null)

MessageBox.Show ("Hey, thats a not a what I want a see", "Error",
MessageBoxButto ns.OK, MessageBoxIcon. Error);

else

{

input = new FileStream(file name, FileMode.Open, FileAccess.Read );

}

try {

pictureBox1.Ima ge = input; //NO WAY, IT HAS AN ERROR THAT SAYS

cannot implicity convert type system.io.files tream to system.drawing. image

}

catch( Exception ex )

[Bradley1234]

Thanks, that worked!

"CiccioPall a" <Ci*********@NO SPAMxiansoft.ne t> wrote in message
news:Of******** ******@TK2MSFTN GP10.phx.gbl...

Image img = Image.FromFile( filename);

pictureBox1.Ima ge = img;

"Bradley123 4" <so*****@yahoo. com> ha scritto nel messaggio
news:wjvpd.9717 $5v1.749@trnddc 06...

Seems simple but Im missing something. In a C# form Ive got a picturebox and a button

I have the File Open dialog linked to the button, but Im drawing a blank

on

how to take the stream and push the thing onto the picturebox.

Here is the code, tia

OpenFileDialog fileChooser = new OpenFileDialog( );

DialogResult result = fileChooser.Sho wDialog();

string filename; //name of file containint data

if (result == DialogResult.Ca ncel)

return;

filename = fileChooser.Fil eName;

if (filename == "" || filename == null)

MessageBox.Show ("Hey, thats a not a what I want a see", "Error",
MessageBoxButto ns.OK, MessageBoxIcon. Error);

else

{

input = new FileStream(file name, FileMode.Open, FileAccess.Read );

}

try {

pictureBox1.Ima ge = input; //NO WAY, IT HAS AN ERROR THAT SAYS

cannot implicity convert type system.io.files tream to system.drawing. image
}

catch( Exception ex )