int and Iconvertible interface

[Rene]

According to the documentation, the int (Int32) type inherits the
Iconvertible interface. This interface has a bunch of methods such as
ToDecimal, ToDouble etc. The thing is that I don't seem to be able to see
any of this methods, even if I make a direct cast in the int. What am I
missing?

Thanks.

[avnrao]

true. VS doesnt display all these methods in intellisense.
you can use explicit interface implementation by casting IConvertible
iconvertInt = (IConvertible)Y ourInt.
and then use methods.

this is because, these types are most frequently used and i guess VS team
considered not to display a deluge of methods in intellisense.
The best way to use is Convert class.

Av.
http://dotnetjunkies.com/WebLog/avnrao
http://www28.brinkster.com/avdotnet

"Rene" <no****@nospam. nospam> wrote in message
news:Oz******** ******@TK2MSFTN GP12.phx.gbl...

According to the documentation, the int (Int32) type inherits the
Iconvertible interface. This interface has a bunch of methods such as
ToDecimal, ToDouble etc. The thing is that I don't seem to be able to see
any of this methods, even if I make a direct cast in the int. What am I
missing?

Thanks.

[Rene]

I don't get it, before I posted this I tryied doing this:

int someInt = 0;
IConvertible interfaceRef = (IConvertible)s omeInt;

Then I used the "interfaceR ef " variable to get a hold of the methods on the
IConvertible interface but I only saw the same thing as if I was using the
"someInt" variable. If it works on your computer then something must be
wrong with my intellisense. Maybe a good reboot will fix the problem.

Thanks.
"avnrao" <av*@newsgroups .com> wrote in message
news:uO******** ******@TK2MSFTN GP15.phx.gbl...

true. VS doesnt display all these methods in intellisense.
you can use explicit interface implementation by casting IConvertible
iconvertInt = (IConvertible)Y ourInt.
and then use methods.

this is because, these types are most frequently used and i guess VS team
considered not to display a deluge of methods in intellisense.
The best way to use is Convert class.

Av.
http://dotnetjunkies.com/WebLog/avnrao
http://www28.brinkster.com/avdotnet

"Rene" <no****@nospam. nospam> wrote in message
news:Oz******** ******@TK2MSFTN GP12.phx.gbl...

According to the documentation, the int (Int32) type inherits the
Iconvertible interface. This interface has a bunch of methods such as
ToDecimal, ToDouble etc. The thing is that I don't seem to be able to see
any of this methods, even if I make a direct cast in the int. What am I
missing?

Thanks.

[Brian Keating EI9FXB]

1) If you cast to Icomparable this should work,
2) The reason that you can't see these methods is because there is an
explicit interfact reference,
this is slightly different, have a look at this quick sample

interface I_Foo
{
void Bar();
}

public class Foo : I_Foo
{
#region I_Foo Members

public void Bar()
{
MessageBox.Show ("hello");
}

#endregion

}

public class Foo2 : I_Foo
{
#region I_Foo Members

void I_Foo.Bar()
{
MessageBox.Show ("I_Foo.Bar" );
}

#endregion

}

"Rene" wrote:

I don't get it, before I posted this I tryied doing this:

int someInt = 0;
IConvertible interfaceRef = (IConvertible)s omeInt;

Then I used the "interfaceR ef " variable to get a hold of the methods on the
IConvertible interface but I only saw the same thing as if I was using the
"someInt" variable. If it works on your computer then something must be
wrong with my intellisense. Maybe a good reboot will fix the problem.

Thanks.
"avnrao" <av*@newsgroups .com> wrote in message
news:uO******** ******@TK2MSFTN GP15.phx.gbl...

true. VS doesnt display all these methods in intellisense.
you can use explicit interface implementation by casting IConvertible
iconvertInt = (IConvertible)Y ourInt.
and then use methods.

this is because, these types are most frequently used and i guess VS team
considered not to display a deluge of methods in intellisense.
The best way to use is Convert class.

Av.
http://dotnetjunkies.com/WebLog/avnrao
http://www28.brinkster.com/avdotnet

"Rene" <no****@nospam. nospam> wrote in message
news:Oz******** ******@TK2MSFTN GP12.phx.gbl...

According to the documentation, the int (Int32) type inherits the
Iconvertible interface. This interface has a bunch of methods such as
ToDecimal, ToDouble etc. The thing is that I don't seem to be able to see
any of this methods, even if I make a direct cast in the int. What am I
missing?

Thanks.

[Daniel Jin]

"avnrao" wrote:

true. VS doesnt display all these methods in intellisense.
you can use explicit interface implementation by casting IConvertible
iconvertInt = (IConvertible)Y ourInt.
and then use methods.

this is because, these types are most frequently used and i guess VS team
considered not to display a deluge of methods in intellisense.
The best way to use is Convert class.

it's not an issue of intellisense not displaying it. when a method of the
interface is explicitly implemented, it's simply not available through the
type. that's a C# language feature, not a VS display feature.
Av.
http://dotnetjunkies.com/WebLog/avnrao
http://www28.brinkster.com/avdotnet

"Rene" <no****@nospam. nospam> wrote in message
news:Oz******** ******@TK2MSFTN GP12.phx.gbl...

According to the documentation, the int (Int32) type inherits the
Iconvertible interface. This interface has a bunch of methods such as
ToDecimal, ToDouble etc. The thing is that I don't seem to be able to see
any of this methods, even if I make a direct cast in the int. What am I
missing?

Thanks.