How to use a user control's constructor which has parameters in design view mode in Visual Studio 2003? ,What is mechanism for generating InitializeCompo nent(){}?

[Ryan Liu]

I have a user control, it must set a property when it is just created, so I set it in its constructor, which has an parameter to specify the property .

For example:
public class ExecQuest : UserControl,IOl eClientSite,IDo cHostUIHandler
{
public ExecQuest(Type showType)
{
this.showType = showType;
}

}

Becuse showType property should not have default value and must be set at the begining, I don't want the user control class has default constructor with no arguements.

But When I put a user control on a form, seems auto-generated code in InitializeCompo nent() {} use control's default constructor.
I can only manually change code in InitializeCompo nent(), which ruined if I go to design mode and InitializeCompo nent() generated again.

public class frmExecute : System.Windows. Forms.Form
{
private void InitializeCompo nent()
{
this.EQ = new ExecQuest(Type. Builder); // manyally edited, it was this.EQ = new ExecQuest()
}
}

What is better way solve this problem?

In other words,
a.. What is mechanism for generating InitializeCompo nent(){}?
b.. How to use a user control's constructor which has parameters in design view mode in Visual Studio 2003?
Thanks a lot!
Ryan