calling other constructor of same class

[Nikola Skoric]

Lets say I have a situation like this:

public class a {
* * * * public a () {
* * * * * * * * //...
* * * * }
** * * * public a (int i) {
* * * * * * * * //...
* * * * }
}

Is there a way to call a() from within a(int i)? Basicly what I'm trying
to achieve is to put all the common code in a (), and in a(int i) just
initialize what I can with the i parameter and than call the a()
construcotor. Would that be possible?

--
"Stara boljka se leci starim lekom...
Dabome vinom, ta nebi valjda mlekom?"

[Pat Richey]

Nikola Skoric wrote:

Lets say I have a situation like this:

public class a {
public a () {
//...
}
public a (int i) {
//...
}
}

Is there a way to call a() from within a(int i)? Basicly what I'm trying
to achieve is to put all the common code in a (), and in a(int i) just
initialize what I can with the i parameter and than call the a()
construcotor. Would that be possible?

no, you want do do something like this:

public class a
{
public a()
{
function_call() ;
}

public a(int i)
{
// stuff with i;
fuction_call();
}

private void function_call()
{
// the common functionality of a() and a(int)
}

[Paul E Collins]

"Nikola Skoric" <ni*******@net4 u.hr> wrote:

Is there a way to call a() from within a(int i)?

public a(int i) : this()
{
// Code dealing with i, to follow the () constructor
}

P.

[Chang]

Pat,

Wondering why can not we call default ctor from a(int i) ?

Thanks.

"Pat Richey" <ri****@uiuc.ed u> wrote in message
news:%2******** **********@TK2M SFTNGP10.phx.gb l...

Nikola Skoric wrote:

Lets say I have a situation like this:

public class a {
public a () {
//...
}
public a (int i) {
//...
}
}

Is there a way to call a() from within a(int i)? Basicly what I'm trying
to achieve is to put all the common code in a (), and in a(int i) just
initialize what I can with the i parameter and than call the a()
construcotor. Would that be possible?

no, you want do do something like this:

public class a
{
public a()
{
function_call() ;
}

public a(int i)
{
// stuff with i;
fuction_call();
}

private void function_call()
{
// the common functionality of a() and a(int)
}

[Mike Edenfield]

Nikola Skoric wrote:

Lets say I have a situation like this:

public class a {
public a () {
//...
}
public a (int i) {
//...
}
}

Is there a way to call a() from within a(int i)? Basicly what I'm trying
to achieve is to put all the common code in a (), and in a(int i) just
initialize what I can with the i parameter and than call the a()
construcotor. Would that be possible?

Only if you want to call it at the very beginning. Attaching " :
this()" to the end of the constructor method instructs the compiler to
call the overloaded constructor with the proper signature. The second
constructor is called *before* the current constructor. It works
similar to how "public a() : base() " works.

public class a {
public a()
{
}

public a ( int i ) : this()
{
this.i = i;
}
}

--Mike

[John Doe]

Try this...

public a() {
}

public a(int I) : this.a() {
}

Chang wrote:

Pat,

Wondering why can not we call default ctor from a(int i) ?

Thanks.

"Pat Richey" <ri****@uiuc.ed u> wrote in message
news:%2******** **********@TK2M SFTNGP10.phx.gb l...

Nikola Skoric wrote:

Lets say I have a situation like this:

public class a {
public a () {
//...
}
public a (int i) {
//...
}
}

Is there a way to call a() from within a(int i)? Basicly what I'm trying
to achieve is to put all the common code in a (), and in a(int i) just
initialize what I can with the i parameter and than call the a()
construcotor . Would that be possible?

no, you want do do something like this:

public class a
{
public a()
{
function_call ();
}

public a(int i)
{
// stuff with i;
fuction_call( );
}

private void function_call()
{
// the common functionality of a() and a(int)
}