I am saving a class by giving it the "Serializab le" attribute, and calling
Serialize. Is there a way that I can pull the value of an individual member
of the class, out of the resulting xml file, without constructing a new
instance of the class deserializing the file into it? In this case, I just
need the value of a string member, and don't want to construct the entire
class to get it. 4 1360
Dave,
The xml that the XmlSerializer generates for a particular type should be
pretty consistent. I would say to take a look at the output that the type
that you are serializing generates, and then construct an XPath query that
you can use to get the value.
For primitive value types, this should be fine, but for propreties that
return class instances, you might have no other option than to run the
XmlSerializer on the whole thing.
Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m
"Dave" <dp*@nospam.eli assen.com> wrote in message
news:%2******** ********@TK2MSF TNGP11.phx.gbl. .. I am saving a class by giving it the "Serializab le" attribute, and calling Serialize. Is there a way that I can pull the value of an individual member of the class, out of the resulting xml file, without constructing a new instance of the class deserializing the file into it? In this case, I just need the value of a string member, and don't want to construct the entire class to get it.
Nicholas:
Thanks for the reply, but I guess I forgot to mention that I'm new to this
stuff. "Xpath query"? How do I do that? Maybe a simple example would make
my question more clear:
Suppose I have a class as follows:
[Serializable] public class foo {
public string member1;
public string member2;
};
And, I serialize it as follows:
....
foo xx = new foo();
xx.member1 = "test value";
xx.member2 = "test value2";
FileStream fs = new FileStream("tes t.xml", FileMode.Create );
SoapFormatter s = new SoapFormatter() ;
s.AssemblyForma t =
System.Runtime. Serialization.F ormatters.Forma tterAssemblySty le.Simple;
s.Serialize(fs, foo);
fs.Close();
So, now I have a file, "test.xml", and I want to pull out the value of
"member1", without deserializing the file into a new instance of foo. How
do I do that?
- Dave
"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard .caspershouse.c om> wrote in
message news:eQ******** ******@TK2MSFTN GP14.phx.gbl... Dave,
The xml that the XmlSerializer generates for a particular type should
be pretty consistent. I would say to take a look at the output that the type that you are serializing generates, and then construct an XPath query that you can use to get the value.
For primitive value types, this should be fine, but for propreties
that return class instances, you might have no other option than to run the XmlSerializer on the whole thing.
Hope this helps.
-- - Nicholas Paldino [.NET/C# MVP] - mv*@spam.guard. caspershouse.co m
"Dave" <dp*@nospam.eli assen.com> wrote in message news:%2******** ********@TK2MSF TNGP11.phx.gbl. ..I am saving a class by giving it the "Serializab le" attribute, and
calling Serialize. Is there a way that I can pull the value of an individual member of the class, out of the resulting xml file, without constructing a new instance of the class deserializing the file into it? In this case, I just need the value of a string member, and don't want to construct the
entire class to get it.
Dave,
Can you post test.xml? Then, we can see the structure, and tell you how
to get the value.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m
"Dave" <dp*@nospam.eli assen.com> wrote in message
news:uv******** ******@TK2MSFTN GP14.phx.gbl... Nicholas:
Thanks for the reply, but I guess I forgot to mention that I'm new to this stuff. "Xpath query"? How do I do that? Maybe a simple example would make my question more clear:
Suppose I have a class as follows:
[Serializable] public class foo { public string member1; public string member2; };
And, I serialize it as follows:
... foo xx = new foo(); xx.member1 = "test value"; xx.member2 = "test value2"; FileStream fs = new FileStream("tes t.xml", FileMode.Create ); SoapFormatter s = new SoapFormatter() ; s.AssemblyForma t = System.Runtime. Serialization.F ormatters.Forma tterAssemblySty le.Simple; s.Serialize(fs, foo); fs.Close();
So, now I have a file, "test.xml", and I want to pull out the value of "member1", without deserializing the file into a new instance of foo. How do I do that?
- Dave
"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard .caspershouse.c om> wrote in message news:eQ******** ******@TK2MSFTN GP14.phx.gbl... Dave,
The xml that the XmlSerializer generates for a particular type should be pretty consistent. I would say to take a look at the output that the type that you are serializing generates, and then construct an XPath query that you can use to get the value.
For primitive value types, this should be fine, but for propreties that return class instances, you might have no other option than to run the XmlSerializer on the whole thing.
Hope this helps.
-- - Nicholas Paldino [.NET/C# MVP] - mv*@spam.guard. caspershouse.co m
"Dave" <dp*@nospam.eli assen.com> wrote in message news:%2******** ********@TK2MSF TNGP11.phx.gbl. .. >I am saving a class by giving it the "Serializab le" attribute, and calling > Serialize. Is there a way that I can pull the value of an individual > member > of the class, out of the resulting xml file, without constructing a new > instance of the class deserializing the file into it? In this case, I > just > need the value of a string member, and don't want to construct the entire > class to get it. > >
Ok. My actual class is more complex, but if you can explain how to do
it with this test code, I think I can figure out the rest. Here's the xml
file produced:
<SOAP-ENV:Envelope xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
xmlns:xsd="http ://www.w3.org/2001/XMLSchema"
xmlns:SOAP-ENC="http://schemas.xmlsoap .org/soap/encoding/"
xmlns:SOAP-ENV="http://schemas.xmlsoap .org/soap/envelope/"
xmlns:clr="http ://schemas.microso ft.com/soap/encoding/clr/1.0"
SOAP-ENV:encodingSty le="http://schemas.xmlsoap .org/soap/encoding/">
<SOAP-ENV:Body>
<a1:foo id="ref-1"
xmlns:a1="http://schemas.microso ft.com/clr/nsassem/XMLTest2/XMLTest2">
<member1 id="ref-3">test value</member1>
<member2 id="ref-4">test value2</member2>
</a1:foo>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
Here's the code I used to produce the above:
using System;
using System.IO;
using System.Runtime. Serialization.F ormatters.Soap;
namespace XMLTest
{
[Serializable] public class foo {
public string member1;
public string member2;
static void Main(string[] args)
{
foo xx = new foo();
xx.member1 = "test value";
xx.member2 = "test value2";
FileStream fs = new FileStream(@"c: \test.xml",
FileMode.Create );
SoapFormatter s = new SoapFormatter() ;
s.AssemblyForma t =
System.Runtime. Serialization.F ormatters.Forma tterAssemblySty le.Simple;
s.Serialize(fs, xx);
fs.Close();
}
};
}
- Dave
"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard .caspershouse.c om> wrote
in message news:<uz******* *******@TK2MSFT NGP11.phx.gbl>. .. Dave,
Can you post test.xml? Then, we can see the structure, and tell
you how to get the value.
-- - Nicholas Paldino [.NET/C# MVP] - mv*@spam.guard. caspershouse.co m
"Dave" <dp*@nospam.eli assen.com> wrote in message news:uv******** ******@TK2MSFTN GP14.phx.gbl... Nicholas:
Thanks for the reply, but I guess I forgot to mention that I'm new
to this stuff. "Xpath query"? How do I do that? Maybe a simple example
would make my question more clear:
Suppose I have a class as follows:
[Serializable] public class foo { public string member1; public string member2; };
And, I serialize it as follows:
... foo xx = new foo(); xx.member1 = "test value"; xx.member2 = "test value2"; FileStream fs = new FileStream("tes t.xml", FileMode.Create ); SoapFormatter s = new SoapFormatter() ; s.AssemblyForma t =
System.Runtime. Serialization.F ormatters.Forma tterAssemblySty le.Simple; s.Serialize(fs, foo); fs.Close();
So, now I have a file, "test.xml", and I want to pull out the value
of "member1", without deserializing the file into a new instance of
foo. How do I do that?
- Dave
"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard .caspershouse.c om>
wrote in message news:eQ******** ******@TK2MSFTN GP14.phx.gbl... Dave,
The xml that the XmlSerializer generates for a particular type
should be pretty consistent. I would say to take a look at the output that
the type that you are serializing generates, and then construct an XPath
query that you can use to get the value.
For primitive value types, this should be fine, but for
propreties that return class instances, you might have no other option than to run
the XmlSerializer on the whole thing.
Hope this helps.
-- - Nicholas Paldino [.NET/C# MVP] - mv*@spam.guard. caspershouse.co m
"Dave" <dp*@nospam.eli assen.com> wrote in message news:%2******** ********@TK2MSF TNGP11.phx.gbl. .. >I am saving a class by giving it the "Serializab le" attribute, and calling > Serialize. Is there a way that I can pull the value of an
individual > member > of the class, out of the resulting xml file, without constructing
a new > instance of the class deserializing the file into it? In this
case, I > just > need the value of a string member, and don't want to construct
the entire > class to get it. > >
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