I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
11  1648 
fsd,
What I would do is store the values in an ArrayList. When you pick the
numbers randomly, remove them from the ArrayList and place into a new
collection. This would require you to change the range of selected random
numbers every time (the first time you pick a random number from the range
1-3, then 1-2, etc, etc). You just have to stop when you have enough
numbers selected. Then, whatever is left over in the ArrayList is what was
not selected.
Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m
"fsd" <sg@hotmial.com > wrote in message
news:bs******** ****@ID-83837.news.uni-berlin.de... I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
Something like this (pseudo-code):
var1 = Random(3);
var2 = Random(3);
while (var2 == var1)
{
var2 = Random(3);
}
--
Dmitriy Lapshin [C# / .NET MVP]
X-Unity Test Studio http://x-unity.miik.com.ua/teststudio.aspx
Bring the power of unit testing to VS .NET IDE
"fsd" <sg@hotmial.com > wrote in message
news:bs******** ****@ID-83837.news.uni-berlin.de... I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
fsd wrote: I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
Add var1 and var2 together
psuedo code;
switch(var1 + var2)
case 3: three is left
case 4: two is left
case 5: one is left
"Sudsy" <bi*********@ho tmail.com> wrote in message
news:3F******** ******@hotmail. com... fsd wrote: I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
Think! What do the numbers 1, 2 and 3 add up to? Add up the two
you know, subtract from 6 and you've got the third.
Simple, but highly effective. Well done.
Seems obvious now, eh?
It does *now*. :)
try this;
int nArrayPos = -1;
for(int x = 0; x < arrayOfVars.Len gth; x++)
{
if(var1 != arrayOfVars[x] & var2 != arrayOfVars[x])
{
nArrayPos = x;
}
}
if(nArrayPos != 01)
MessageBox.Show (arrayOfVars[x].ToString() + " is not beeing used");
"fsd" <sg@hotmial.com > wrote in message
news:bs******** ****@ID-83837.news.uni-berlin.de... I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
fsd wrote:
I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
if (var1 != var2)
System.out.prin tln ( (6 - var1 - var2) + " is missing" );
else
System.out.prin tln ("Two values are missing, you liar!");
-- Er*********@sun .com
Sorry, the last if should have been;
if(nArrayPos != -1)
"Marco Martin" <ma**********@s ympatico.ca> wrote in message
news:9Y******** ************@ne ws20.bellglobal .com... try this;
int nArrayPos = -1;
for(int x = 0; x < arrayOfVars.Len gth; x++)
{
if(var1 != arrayOfVars[x] & var2 != arrayOfVars[x])
{
nArrayPos = x;
}
}
if(nArrayPos != 01)
MessageBox.Show (arrayOfVars[x].ToString() + " is not beeing used");
"fsd" <sg@hotmial.com > wrote in message
news:bs******** ****@ID-83837.news.uni-berlin.de... I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
fsd wrote: I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
Think more mathematically. Sum the numbers you have together, and
deduct them from the sum of all three numbers. No loops required.
Brad BARCLAY
--
=-=-=-=-=-=-=-=-=
From the OS/2 WARP v4.5 Desktop of Brad BARCLAY.
The jSyncManager Project: http://www.jsyncmanager.org
Unless I'm missing something, this would not work because theoretically you
could get "1" as your answer every time...and that would be stored in each
element of the array list.
Eric
"Nicholas Paldino [.NET/C# MVP]" <mv*@spam.guard .caspershouse.c om> wrote in
message news:#r******** ******@TK2MSFTN GP12.phx.gbl... fsd,
What I would do is store the values in an ArrayList. When you pick
the numbers randomly, remove them from the ArrayList and place into a new
collection. This would require you to change the range of selected random
numbers every time (the first time you pick a random number from the range
1-3, then 1-2, etc, etc). You just have to stop when you have enough
numbers selected. Then, whatever is left over in the ArrayList is what
was not selected.
Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard. caspershouse.co m
"fsd" <sg@hotmial.com > wrote in message
news:bs******** ****@ID-83837.news.uni-berlin.de... I have three numbers - 1, 2 & 3.
A randomly selected one of the three are stored in 'var1', and another
randomly selected one is in 'var2'.
How do I find out the number that is left over?
I tried a while loop but I couldn't get it to work...
TIA
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