Im using Environment.Get CommandLineArgs ().
However some of the arguemtns passed in have spaces, so I enclosed them in
"".
For example:
"c:\temp\My area\"
The problem is when I access this as an element of the string array it
treating the last \" (And maybe others" as escape characters. So array
element [1] actually gets:
"c:\\temp\\ My area\""
or
@"c:\temp\My area""
Am I just missing something obvious?
--
Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/
"Programmin g is an art form that fights back" 16 9527
Chad Z. Hower aka Kudzu wrote: Im using Environment.Get CommandLineArgs ().
However some of the arguemtns passed in have spaces, so I enclosed them in "".
For example:
"c:\temp\My area\"
The problem is when I access this as an element of the string array it treating the last \" (And maybe others" as escape characters. So array element [1] actually gets:
"c:\\temp\\ My area\""
or
@"c:\temp\My area""
Am I just missing something obvious?
What's wrong with @"c:\temp\my area"? You use @-quoting when you don't want
escape sequences to be processed. That's what @-quoting is for and the
example you list is a textbook example of when to use it.
--
Tom Porterfield
MS-MVP MCE http://support.telop.org
Please post all follow-ups to the newsgroup only.
"Tom Porterfield" <tp******@mvps. org> wrote in
news:e#******** ******@TK2MSFTN GP12.phx.gbl: What's wrong with @"c:\temp\my area"? You use @-quoting when you don't want escape sequences to be processed. That's what @-quoting is for and the example you list is a textbook example of when to use it.
So Im supposed to tell my users that because of a problem in C# that unlike
any other command line utilty they have to pass argumetns prefixed with a @?
So now we have type DOS comamnds like this:
copy @"c:\my area\*.*" @"d:\temp area\"
?
--
Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/
"Programmin g is an art form that fights back"
This may be a problem with the Windows command line
interpreter, not .NET. The CLI sees a '\"' as a literal quote.
So you get a path with a quote char at the end instead of
a backslash.
The solution is to not end paths with a backslash
or to discard any quotes at the end of the path
with a String.TrimEnd.
Chad Z. Hower aka Kudzu wrote... Im using Environment.Get CommandLineArgs ().
However some of the arguemtns passed in have spaces, so I enclosed them in "".
For example:
"c:\temp\My area\"
The problem is when I access this as an element of the string array it treating the last \" (And maybe others" as escape characters. So array element [1] actually gets:
"c:\\temp\\ My area\""
or
@"c:\temp\My area""
Am I just missing something obvious? -- Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/ "Programmin g is an art form that fights back"
This may be a problem with the Windows command line
interpreter, not .NET. The CLI sees a '\"' as a literal quote.
So you get a path with a quote char at the end instead of
a backslash.
The solution is to not end paths with a backslash
or to discard any quotes at the end of the path
with a String.TrimEnd.
Chad Z. Hower aka Kudzu wrote... Im using Environment.Get CommandLineArgs ().
However some of the arguemtns passed in have spaces, so I enclosed them in "".
For example:
"c:\temp\My area\"
The problem is when I access this as an element of the string array it treating the last \" (And maybe others" as escape characters. So array element [1] actually gets:
"c:\\temp\\ My area\""
or
@"c:\temp\My area""
Am I just missing something obvious? -- Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/ "Programmin g is an art form that fights back"
jerry <je***@nospam.c om> wrote in
news:MP******** *************** *@msnews.micros oft.com: The solution is to not end paths with a backslash or to discard any quotes at the end of the path with a String.TrimEnd.
This is not a solution at all. Am I supposed to tell users "Dont put a
trailing /, there is a bug in Windows".
And the bigger concern is, is it just doing this at the end, or is it
possibly escaping other characters internally too? This is a fairly big bug
that I've seen lots of confirmations from other users.
I would hope MS plans to fix this.
--
Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/
"Programmin g is an art form that fights back"
jerry <je***@nospam.c om> wrote in
news:MP******** *************** *@msnews.micros oft.com: The solution is to not end paths with a backslash or to discard any quotes at the end of the path with a String.TrimEnd.
This is not a solution at all. Am I supposed to tell users "Dont put a
trailing /, there is a bug in Windows".
And the bigger concern is, is it just doing this at the end, or is it
possibly escaping other characters internally too? This is a fairly big bug
that I've seen lots of confirmations from other users.
I would hope MS plans to fix this.
--
Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/
"Programmin g is an art form that fights back"
jerry <je***@nospam.c om> wrote: This may be a problem with the Windows command line interpreter, not .NET. The CLI sees a '\"' as a literal quote. So you get a path with a quote char at the end instead of a backslash.
The solution is to not end paths with a backslash or to discard any quotes at the end of the path with a String.TrimEnd.
Hmm... I see this problem with a .NET app that takes parameters, but
not with the following Delphi equivalent:
program Project1;
{$APPTYPE CONSOLE}
uses
SysUtils;
var
I: Integer;
begin
for I := 1 to ParamCount do
WriteLn(ParamSt r(I));
ReadLn;
end.
Unless the ParamStr() is working around this...
jerry <je***@nospam.c om> wrote: This may be a problem with the Windows command line interpreter, not .NET. The CLI sees a '\"' as a literal quote. So you get a path with a quote char at the end instead of a backslash.
The solution is to not end paths with a backslash or to discard any quotes at the end of the path with a String.TrimEnd.
Hmm... I see this problem with a .NET app that takes parameters, but
not with the following Delphi equivalent:
program Project1;
{$APPTYPE CONSOLE}
uses
SysUtils;
var
I: Integer;
begin
for I := 1 to ParamCount do
WriteLn(ParamSt r(I));
ReadLn;
end.
Unless the ParamStr() is working around this...
C# Learner <cs****@learner .here> wrote in
news:vh******** *************** *********@4ax.c om: Unless the ParamStr() is working around this...
Not that I know of. I've looked at the source before for this and didnt see
any work arounds unless a new one was added for Delphi 8.
--
Chad Z. Hower (a.k.a. Kudzu) - http://www.hower.org/Kudzu/
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