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OpenFileDialog !

Hello,

using openfiledialog, how can I retrieve the path ?

thx
Nov 15 '05 #1
7 2216
L#
On Wed, 4 Feb 2004 19:53:38 -0800, "C# newbie"
<rs****@otxrese arch.com> wrote:
Hello,

using openfiledialog, how can I retrieve the path ?

thx


OpenFileDialog o = new OpenFileDialog( );
if (o.ShowDialog() == DialogResult.OK )
{
string fn = Path.GetFileNam e(o.FileName);
string path = Path.GetDirecto ryName(o.FileNa me);
}
--
Ludwig
mailto:ludwig_( nospamplease)st uyck@pandora(no spamplease).be
Nov 15 '05 #2
Hi there,

First add a reference to System.Design.d ll and then the following code
should work:

using System;
using System.Windows. Forms;
using System.Windows. Forms.Design;
public class BrowseForFolder : FolderNameEdito r
{
FolderNameEdito r.FolderBrowser bDialog;

public BrowseForFolder ()
{
bDialog = new FolderNameEdito r.FolderBrowser ();
}

public string browseDialog(st ring sTitle)
{
bDialog.Descrip tion = sTitle;
bDialog.StartLo cation =
FolderNameEdito r.FolderBrowser Folder.MyComput er;
bDialog.Style = FolderNameEdito r.FolderBrowser Styles.Restrict ToDomain;
bDialog.ShowDia log();
return bDialog.Directo ryPath;
}
~BrowseForFolde r()
{
bDialog.Dispose ();
}
}

This code is from here:
http://www.planet-source-code.com/vb...odeId=275&lngW
Id=10

The article says you can call the code like so:

BrowseForFolder myDialog = new BrowseForFolder ();
MessageBox.Show (myDialog.brows eDialog("Dialog Title Goes Here");

But if you want to be able to determine what the user pressed, you can do
something like the following:

DialogResult result = myDialog.ShowDi alog()

You can find more about the DialogResult at:
http://msdn.microsoft.com/library/de...s/cpref/html/f
rlrfsystemwindo wsformsdialogre sultclasstopic. asp

Good luck!

Mack D. Male
MVP Visual Developer - Academic
"C# newbie" <rs****@otxrese arch.com> wrote in message
news:#g******** ******@TK2MSFTN GP12.phx.gbl...
Hello,

using openfiledialog, how can I retrieve the path ?

thx

Nov 15 '05 #3
Thanks. The thing is I'm useing the path either but compiler complains on
path!
Any suggestions ?

Regards


"L#" <ludwig_(nospam please)stuyck@p andora(nospampl ease).be> wrote in message
news:1o******** *************** *********@4ax.c om...
On Wed, 4 Feb 2004 19:53:38 -0800, "C# newbie"
<rs****@otxrese arch.com> wrote:
Hello,

using openfiledialog, how can I retrieve the path ?

thx


OpenFileDialog o = new OpenFileDialog( );
if (o.ShowDialog() == DialogResult.OK )
{
string fn = Path.GetFileNam e(o.FileName);
string path = Path.GetDirecto ryName(o.FileNa me);
}
--
Ludwig
mailto:ludwig_( nospamplease)st uyck@pandora(no spamplease).be

Nov 15 '05 #4
L#
On Thu, 5 Feb 2004 12:39:56 -0800, "C# newbie"
<rs****@otxrese arch.com> wrote:
Thanks. The thing is I'm useing the path either but compiler complains on
path!
Any suggestions ?

Regards


I'm sorry, I'm afraid I don't understand your question?

--
Ludwig
mailto:ludwig_( nospamplease)st uyck@pandora(no spamplease).be
Nov 15 '05 #5
Hi Ludwig,

Thanks for your quick response. Regarding your code :

OpenFileDialog o = new OpenFileDialog( );
if (o.ShowDialog() == DialogResult.OK )
{
string fn = Path.GetFileNam e(o.FileName);
string path = Path.GetDirecto ryName(o.FileNa me);
}

the compiler complains about "Path". Also, after adding a dot to "Path"
Intellisence does't come upand doesn't show any method related. I was
assuming that Path is a member of the OpenFileDialog class.

Any idea?

Thanks in advance

"L#" <ludwig_(nospam please)stuyck@p andora(nospampl ease).be> wrote in message
news:vv******** *************** *********@4ax.c om...
On Thu, 5 Feb 2004 12:39:56 -0800, "C# newbie"
<rs****@otxrese arch.com> wrote:
Thanks. The thing is I'm useing the path either but compiler complains on
path!
Any suggestions ?

Regards


I'm sorry, I'm afraid I don't understand your question?

--
Ludwig
mailto:ludwig_( nospamplease)st uyck@pandora(no spamplease).be

Nov 15 '05 #6
L#
On Thu, 5 Feb 2004 13:49:57 -0800, "C# newbie"
<rs****@otxrese arch.com> wrote:
Hi Ludwig,

Thanks for your quick response. Regarding your code :

OpenFileDial og o = new OpenFileDialog( );
if (o.ShowDialog() == DialogResult.OK )
{
string fn = Path.GetFileNam e(o.FileName);
string path = Path.GetDirecto ryName(o.FileNa me);
}

the compiler complains about "Path". Also, after adding a dot to "Path"
Intellisence does't come upand doesn't show any method related. I was
assuming that Path is a member of the OpenFileDialog class.

Any idea?


No, Path is a System.IO class, so use System.IO.Path, or put "using
System.IO;" on top.
--
Ludwig
mailto:ludwig_( nospamplease)st uyck@pandora(no spamplease).be
Nov 15 '05 #7
Yes, you're right. works.

thanks a lot
"L#" <ludwig_(nospam please)stuyck@p andora(nospampl ease).be> wrote in message
news:u1******** *************** *********@4ax.c om...
On Thu, 5 Feb 2004 13:49:57 -0800, "C# newbie"
<rs****@otxrese arch.com> wrote:
Hi Ludwig,

Thanks for your quick response. Regarding your code :

OpenFileDial og o = new OpenFileDialog( );
if (o.ShowDialog() == DialogResult.OK )
{
string fn = Path.GetFileNam e(o.FileName);
string path = Path.GetDirecto ryName(o.FileNa me);
}

the compiler complains about "Path". Also, after adding a dot to "Path"
Intellisence does't come upand doesn't show any method related. I was
assuming that Path is a member of the OpenFileDialog class.

Any idea?


No, Path is a System.IO class, so use System.IO.Path, or put "using
System.IO;" on top.
--
Ludwig
mailto:ludwig_( nospamplease)st uyck@pandora(no spamplease).be

Nov 15 '05 #8

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