I am trying ot get a certain no of records from a DataView. I am looking ot
do like a Top 15 in Sql, Is there a easy way to do this or should I loop till
the count?
Appreciate any help.
--
Live one day at a time. 3 1025
I think you have to loop.
Karl
--
MY ASP.Net tutorials http://www.openmymind.net/
"redmond" <re*****@discus sions.microsoft .com> wrote in message
news:03******** *************** ***********@mic rosoft.com... I am trying ot get a certain no of records from a DataView. I am looking
ot do like a Top 15 in Sql, Is there a easy way to do this or should I loop
till the count? Appreciate any help.
-- Live one day at a time.
I use two approaches;
Form the Sql with the "TOP n" constraint, do the query, and make the
resulting DataTable your data source (if you're using databinding).
When I'm doing pagination, I use DataAdapter.Fil l (). As I understand it,
Fill isn't really much more efficient than writing a loop, but the code
looks far cleaner.
"redmond" <re*****@discus sions.microsoft .com> wrote in message
news:03******** *************** ***********@mic rosoft.com... I am trying ot get a certain no of records from a DataView. I am looking
ot do like a Top 15 in Sql, Is there a easy way to do this or should I loop
till the count? Appreciate any help.
-- Live one day at a time.
Thank you all, I finally found the PagedDataSource thru which I cna pick the
no of records I want.
"MWells" wrote: I use two approaches;
Form the Sql with the "TOP n" constraint, do the query, and make the resulting DataTable your data source (if you're using databinding).
When I'm doing pagination, I use DataAdapter.Fil l (). As I understand it, Fill isn't really much more efficient than writing a loop, but the code looks far cleaner.
"redmond" <re*****@discus sions.microsoft .com> wrote in message news:03******** *************** ***********@mic rosoft.com... I am trying ot get a certain no of records from a DataView. I am looking ot do like a Top 15 in Sql, Is there a easy way to do this or should I loop till the count? Appreciate any help.
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