say i have a string that is "hello this is my string and i like it very
much" and i want to insert a newline at every 20th character, how could i go
about doing this? 8 4720
Joe Reynolds wrote:
say i have a string that is "hello this is my string and i like it
very much" and i want to insert a newline at every 20th character,
how could i go about doing this?
I'm sure someone will post a regex solution for this, but until then:
dim buffer, i, newstring,s
s="hello this is my string and i like it very much"
buffer=20
for i = 1 to len(s) step 20
newstring=newstring & mid(s,i,20) & vbcrlf
next
msgbox newstring
--
Microsoft MVP -- ASP/ASP.NET
Please reply to the newsgroup. The email account listed in my From
header is my spam trap, so I don't check it very often. You will get a
quicker response by posting to the newsgroup.
that just might work
:)
"Bob Barrows [MVP]" <re******@NOyahoo.SPAMcomwrote in message
news:%2***************@TK2MSFTNGP06.phx.gbl...
Joe Reynolds wrote:
>say i have a string that is "hello this is my string and i like it very much" and i want to insert a newline at every 20th character, how could i go about doing this?
I'm sure someone will post a regex solution for this, but until then:
dim buffer, i, newstring,s
s="hello this is my string and i like it very much"
buffer=20
for i = 1 to len(s) step 20
newstring=newstring & mid(s,i,20) & vbcrlf
next
msgbox newstring
--
Microsoft MVP -- ASP/ASP.NET
Please reply to the newsgroup. The email account listed in my From
header is my spam trap, so I don't check it very often. You will get a
quicker response by posting to the newsgroup.
Bob Barrows [MVP] wrote:
dim buffer, i, newstring,s
s="hello this is my string and i like it very much"
buffer=20
for i = 1 to len(s) step 20
newstring=newstring & mid(s,i,20) & vbcrlf
next
msgbox newstring
Won't that put an extra line break at the end, Bob?
--
Dave Anderson
Unsolicited commercial email will be read at a cost of $500 per message. Use
of this email address implies consent to these terms.
that doesnt hurt me
:)
"Dave Anderson" <NY**********@spammotel.comwrote in message
news:%2****************@TK2MSFTNGP05.phx.gbl...
Bob Barrows [MVP] wrote:
>dim buffer, i, newstring,s s="hello this is my string and i like it very much" buffer=20 for i = 1 to len(s) step 20 newstring=newstring & mid(s,i,20) & vbcrlf next msgbox newstring
Won't that put an extra line break at the end, Bob?
--
Dave Anderson
Unsolicited commercial email will be read at a cost of $500 per message.
Use of this email address implies consent to these terms.
Dave Anderson wrote:
Bob Barrows [MVP] wrote:
>dim buffer, i, newstring,s s="hello this is my string and i like it very much" buffer=20 for i = 1 to len(s) step 20 newstring=newstring & mid(s,i,20) & vbcrlf next msgbox newstring
Won't that put an extra line break at the end, Bob?
Ummmm ... errr. .. I left that as an exercise for the reader ... yeah,
that's the ticket!
--
Microsoft MVP - ASP/ASP.NET
Please reply to the newsgroup. This email account is my spam trap so I
don't check it very often. If you must reply off-line, then remove the
"NO SPAM"
"Bob Barrows [MVP]" <re******@NOyahoo.SPAMcomwrote in message
news:%2***************@TK2MSFTNGP06.phx.gbl...
Joe Reynolds wrote:
say i have a string that is "hello this is my string and i like it
very much" and i want to insert a newline at every 20th character,
how could i go about doing this?
I'm sure someone will post a regex solution for this, but until then:
Here's then:-
s = InsertStringAtInterval(s, vbCrLf, 20))
Function InsertStringAtInterval(rsSource, rsInsert, rlInterval)
Dim rgx
Set rgx = new RegExp
rgx.Pattern = "([\s\S]{" & rlInterval & "})"
rgx.Global = true
InsertStringAtInterval = rgx.Replace(rsSource, "$1" & rsInsert)
End Function
BTW Joe, I still think you should persue a different solution than this.
If you use this in the TD you will actually need:-
s = InsertStringAtInterval(Server.HTMLEncode(s), "<br />", 20))
dim buffer, i, newstring,s
s="hello this is my string and i like it very much"
buffer=20
for i = 1 to len(s) step 20
newstring=newstring & mid(s,i,20) & vbcrlf
next
msgbox newstring
--
Microsoft MVP -- ASP/ASP.NET
Please reply to the newsgroup. The email account listed in my From
header is my spam trap, so I don't check it very often. You will get a
quicker response by posting to the newsgroup.
thank you. that works great, but i had another thought (posted a new
question also)
what i want to do is first check the users input. if i find any strings of
characters that are longer than 40 characters that dont contain a space THEN
i would pass it to your function. as long as there is at least 1 space for
every 40 chars, im ok
"Anthony Jones" <An*@yadayadayada.comwrote in message
news:%2****************@TK2MSFTNGP03.phx.gbl...
>
"Bob Barrows [MVP]" <re******@NOyahoo.SPAMcomwrote in message
news:%2***************@TK2MSFTNGP06.phx.gbl...
>Joe Reynolds wrote:
say i have a string that is "hello this is my string and i like it
very much" and i want to insert a newline at every 20th character,
how could i go about doing this?
I'm sure someone will post a regex solution for this, but until then:
Here's then:-
s = InsertStringAtInterval(s, vbCrLf, 20))
Function InsertStringAtInterval(rsSource, rsInsert, rlInterval)
Dim rgx
Set rgx = new RegExp
rgx.Pattern = "([\s\S]{" & rlInterval & "})"
rgx.Global = true
InsertStringAtInterval = rgx.Replace(rsSource, "$1" & rsInsert)
End Function
BTW Joe, I still think you should persue a different solution than this.
If you use this in the TD you will actually need:-
s = InsertStringAtInterval(Server.HTMLEncode(s), "<br />", 20))
>dim buffer, i, newstring,s s="hello this is my string and i like it very much" buffer=20 for i = 1 to len(s) step 20 newstring=newstring & mid(s,i,20) & vbcrlf next msgbox newstring -- Microsoft MVP -- ASP/ASP.NET Please reply to the newsgroup. The email account listed in my From header is my spam trap, so I don't check it very often. You will get a quicker response by posting to the newsgroup.
every 40 chars, im ok
How did you determine that 40 chars is OK?
Is that when I have my font size set to any of smallest, smaller, medium,
larger or largest in IE, or use anthing but normal in FireFox?
Bob Lehmann
"Joe Reynolds" <js@js.comwrote in message
news:%2****************@TK2MSFTNGP02.phx.gbl...
thank you. that works great, but i had another thought (posted a new
question also)
what i want to do is first check the users input. if i find any strings of
characters that are longer than 40 characters that dont contain a space
THEN
i would pass it to your function. as long as there is at least 1 space for
every 40 chars, im ok
"Anthony Jones" <An*@yadayadayada.comwrote in message
news:%2****************@TK2MSFTNGP03.phx.gbl...
"Bob Barrows [MVP]" <re******@NOyahoo.SPAMcomwrote in message
news:%2***************@TK2MSFTNGP06.phx.gbl...
Joe Reynolds wrote:
say i have a string that is "hello this is my string and i like it
very much" and i want to insert a newline at every 20th character,
how could i go about doing this?
I'm sure someone will post a regex solution for this, but until then:
Here's then:-
s = InsertStringAtInterval(s, vbCrLf, 20))
Function InsertStringAtInterval(rsSource, rsInsert, rlInterval)
Dim rgx
Set rgx = new RegExp
rgx.Pattern = "([\s\S]{" & rlInterval & "})"
rgx.Global = true
InsertStringAtInterval = rgx.Replace(rsSource, "$1" & rsInsert)
End Function
BTW Joe, I still think you should persue a different solution than
this.
If you use this in the TD you will actually need:-
s = InsertStringAtInterval(Server.HTMLEncode(s), "<br />", 20))
dim buffer, i, newstring,s
s="hello this is my string and i like it very much"
buffer=20
for i = 1 to len(s) step 20
newstring=newstring & mid(s,i,20) & vbcrlf
next
msgbox newstring
--
Microsoft MVP -- ASP/ASP.NET
Please reply to the newsgroup. The email account listed in my From
header is my spam trap, so I don't check it very often. You will get a
quicker response by posting to the newsgroup.
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