I feel really dumb asking this but I'm not sure why it isn't working.
I have a form that has a text field. You type a number into the text field, it gets concatenated with a string, then gets put into the table as a string in the field "Survey_Num ".
Press a button on the form and another form pops up. There is a "Survey_Num " field in the table behind this form as well and they are tied in a one-to-many relationship.
I want the value on the first form to show up in the field on the 2nd form.
I am guessing that it is not showing up because technically the value hasn't entered the table from the first form.
How do I force Access to enter the data when I press the button to go to the second form? I've tried using a close command to close the first form when the 2nd form is opening, thinking that will enter the info into the table but no dice.
Seems simple but I am stumped - any ideas?
Any code I can provide?
Form 1 = frm_Survey with unbound field txt_SurveyNum where user enters an integer and invisible field txt_SurveyNumID that is bound to Survey_Num of Survey table.
txt_SurveyNum has LostFocus event: - Private Sub txt_SurveyNum_LostFocus()
-
Me.txt_SurveyNumID = Me.OpenArgs & Me.txt_SurveyNum
-
End Sub
The OpenArgs is passed by another form that opens frm_Survey.
Form 2 = frm_Replicate with Survey_Num field and control source is field of same name in table. Because it is in a relationship with the field of same name in the other table I didn't think I'd have to put any special query or code on it?
thanks in advance for any help!
melissa
16 1808 Rabbit 12,516
Recognized Expert Moderator MVP
Hmm, it might be because the field is invisible. I'm not sure as I haven't tested this but before you assign the value in the Lost Focus event, try making it visible, assign the value, and then make it invisible again.
I tried everything with the field visible but it doesn't show up on the 2nd form.
Rabbit 12,516
Recognized Expert Moderator MVP
Are you trying to pass the concatenated string to yet another form?
Yes. Sort of. I would expect that since they are linked (Survey_Num is primary key of Survey table and foreign key in Replicate table) it would show up simply by being bound. Sorry, let me expand.
I have a switchboard with 3 buttons. Each button opens the same form but passes a different string via the OpenArgs option of the Open command. For example, - stDocName = "frm_Survey"
-
DoCmd.OpenForm stDocName, , , , , , "TR"
.
On frm_Survey is the unbound textbox "txt_SurveyNum" . The user enters a number there ("3"). Then on the hidden/invisible bound textbox ("txt_SurveyNum ID") is the LostFocus event that concatenates the TR with 3 to make TR3. This is the value that is entered in the Survey_Num field of tbl_Survey.
frm_Survey has a button to open frm_Replicate. On the form is a bound textbox called "txt_SurveyNum" . It is bound to the field Survey_Num on tbl_Replicate, which is acting as a foreign key to the Survey_Num field on tbl_Survey.
My hope is that when frm_Replicate is opened the value "TR3" shows up in the textbox that is bound to Survey_Num.
I hope this makes sense!
Rabbit 12,516
Recognized Expert Moderator MVP
Yes. Sorry, let me expand.
I have a switchboard with 3 buttons. Each button opens the same form but passes a different string via the OpenArgs option of the Open command. For example, - stDocName = "frm_Survey"
-
DoCmd.OpenForm stDocName, , , , , , "TR"
.
On frm_Survey is the unbound textbox "txt_SurveyNum" . The user enters a number there ("3"). Then on the hidden/invisible bound textbox ("txt_SurveyNum ID") is the LostFocus event that concatenates the TR with 3 to make TR3. This is the value that is entered in the Survey_Num field of tbl_Survey.
frm_Survey has a button to open frm_Replicate. On the form is a bound textbox called "txt_SurveyNum" . It is bound to the field Survey_Num on tbl_Replicate, which is acting as a foreign key to the Survey_Num field on tbl_Survey.
My hope is that when frm_Replicate is opened the value "TR3" shows up in the textbox that is bound to Survey_Num.
I hope this makes sense!
When you open the form you're going to have to assign the concatenated variable. - stDocName = "frm_Replicate"
-
DoCmd.OpenForm stDocName
-
Forms!frm_Replicate!Survey_Num = Me.Survey_Num
-
DoCmd.Close acForm, "frm_Survey"
When you open the form you're going to have to assign the concatenated variable. - stDocName = "frm_Replicate"
-
DoCmd.OpenForm stDocName
-
Forms!frm_Replicate!Survey_Num = Me.Survey_Num
-
DoCmd.Close acForm, "frm_Survey"
Ahh! That works great! Can you explain to me what this line means? - Forms!frm_Replicate!Survey_Num = Me.Survey_Num
I assume it means that Survey_Num on frm_Replicate equals Surevy_Num on the current (frm_Survey) form?
Moving forward . . . on frm_Replicate I have a button to add a new record (I am going to disable the the standard Access built-in buttons on the form to really "dumb it down" for the user). How can I carry the value again to the next record? Basically I need to keep carrying "TR3" until the user hits the button to stop adding Replicates, closes it and goes back to frm_Survey to start a new Survey ("TR4").
Rabbit 12,516
Recognized Expert Moderator MVP
Ahh! That works great! Can you explain to me what this line means? - Forms!frm_Replicate!Survey_Num = Me.Survey_Num
I assume it means that Survey_Num on frm_Replicate equals Surevy_Num on the current (frm_Survey) form?
Moving forward . . . on frm_Replicate I have a button to add a new record (I am going to disable the the standard Access built-in buttons on the form to really "dumb it down" for the user). How can I carry the value again to the next record? Basically I need to keep carrying "TR3" until the user hits the button to stop adding Replicates, closes it and goes back to frm_Survey to start a new Survey ("TR4").
Yes, that's exactly what it means.
In this case, rather than assigning the Survey_Num directly from the original form, pass it as in OpenArgs. - DoCmd.OpenForm "frm_Replicate",,,,,, Me.Survey_Num
Then in the on open of the form and when they click the new button, you can have it assign Me.OpenArgs to Me.Survey_Num.
Okay, so switch the code around a bit? Let me try that . . .
Rabbit 12,516
Recognized Expert Moderator MVP
That's right, let us know how you get along.
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