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DateAdd Function - error when adding one year?

153 New Member
I'm using the date add function and for some reason I'm getting an error when I try to add a single year to a date but no error when I try to add more than a single year. can anyone figure out why this may be?

example: DateAdd("yyyy", 1, recSet7.Fields( "DateofContract "))
Jan 18 '07
23 5026
cyberdwarf
218 Recognized Expert New Member
Good luck & keep the thread alive

Steve
Jan 18 '07 #11
Kosmos
153 New Member
Thanks...unfort unately that doesn't really work. The date will be different each time and so I have to pull it from a table in date format which will be 9/7/2005 and not 09/07/2005. This is confusing.

oh and I also tried it as a text box instead of a date box and did 09/07/2005 but this did not work either.
Jan 18 '07 #12
cyberdwarf
218 Recognized Expert New Member
OK

You could try to preformat the date into a string. then use the string variable in the function.

It may be that the DateAdd function is misinterpreting the date - I have seen this happen with dates in both Access & SQL functions...

HTH

Steve
Jan 18 '07 #13
cyberdwarf
218 Recognized Expert New Member
OK, last try!

Just add double-quotes round the date field, thus:-
Expand|Select|Wrap|Line Numbers
  1. Dim tmp As String
  2. tmp = recSet7.Fields("DateofContract") 
  3. DateAdd("yyyy", 1, tmp)
Works here!
Steve
Jan 18 '07 #14
cyberdwarf
218 Recognized Expert New Member
Is Access switching the day and month around?

Steve
Jan 18 '07 #15
Kosmos
153 New Member
hmm well perhaps that would work...I found another solution, however, that brings me to believe that perhaps the problem lied in the fact that "DateOfContract " is a required field (not sure why this would cause a problem) but this works as well...


[PHP] recSet7.Open "tblContrac ts", con7, adOpenKeyset, adLockOptimisti c
recSet7.MoveFir st
Do Until recSet7.EOF
If IsNull(recSet7. Fields("Renewal Date")) And recSet7.Fields( "TermOfContract InYears") <> 0 And recSet7.Fields( "ContinuousCont ract") = True Then
recSet7.Fields( "RenewalDat e") = recSet7.Fields( "DateOfContract ")
Do Until recSet7.Fields( "RenewalDat e") > Date
If recSet7.Fields( "TermOfContract InYears") = 1 Then
recSet7.Fields( "RenewalDat e") = DateAdd("yyyy", 1, recSet7.Fields( "RenewalDat e"))
Else
recSet7.Fields( "RenewalDat e") = DateAdd("yyyy", recSet7.Fields( "TermOfContract InYears"), recSet7.Fields( "RenewalDat e"))
End If
Loop
recSet7.Fields( "RenewalDat e") = DateAdd("d", (-1), recSet7.Fields( "RenewalDat e"))

ElseIf Not IsNull(recSet7. Fields("Renewal Date")) And recSet7.Fields( "TermOfContract InYears") <> 0 And recSet7.Fields( "ContinuousCont ract") = True Then
If recSet7.Fields( "RenewalDat e") <= Date Then
Me.txtReference = recSet7.Fields( "DatabaseRefere nceNumber")
DoCmd.OpenQuery ("UpdateAddedTo Outlook")
Do Until recSet7.Fields( "RenewalDat e") > Date
If recSet7.Fields( "TermOfContract InYears") = 1 Then
recSet7.Fields( "RenewalDat e") = DateAdd("yyyy", 1, recSet7.Fields( "RenewalDat e"))
Else
recSet7.Fields( "RenewalDat e") = DateAdd("yyyy", recSet7.Fields( "TermOfContract InYears"), recSet7.Fields( "RenewalDat e"))
End If
Loop
End If
End If
recSet7.MoveNex t
Loop
recSet7.Close[/PHP]

Thanks for all the help!
Jan 18 '07 #16
Kosmos
153 New Member
by the way I tried the tmp thing as well...this did not work..so perhaps the misinterpretati on is because I am doing

recSet1.Fields( "A") = DateAdd("yyyy", #, recSet1.Fields( "B"))

maybe you can only do

recSet1.Fields( "A") = DateAdd("yyyy", #, recSet1.Fields( "A"))

??
Jan 18 '07 #17
cyberdwarf
218 Recognized Expert New Member
Either should work, so long as a valid date is returned by DatAdd

Steve
Jan 18 '07 #18
Killer42
8,435 Recognized Expert Expert
This works perfectly:
Expand|Select|Wrap|Line Numbers
  1. DateAdd("yyyy", 1,"09/07/2005"
Returns 09/07/2006
However:
Expand|Select|Wrap|Line Numbers
  1. DateAdd("yyyy", 1,9/7/2005
Returns 30/12/1900 00:00:55
I expect that's because in the second case you're using a numeric expression which would evaluate to around .00064125. That is, 9 divided by 7 (about 1.3) divided by 2,005. This very small number is presumably interpreted, in a date/time context, as about 55 seconds after midnight on the "first" day.
Jan 18 '07 #19
cyberdwarf
218 Recognized Expert New Member
That's why I suggested using a string...

Steve
Jan 18 '07 #20

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