Access 2000 question
Hi any help or advise required if possible
i am trying to create a formula for a field. here is what i have
currently
rem:
IIf(Time()<[Hours]![StartTime],MinToTime(([Hours]*60)),MinToTime ((([Hours]*60))-([Hours]![Non-Productive]*60)-(IIf(Time()>"09 :00:00"
And
Time()<="10:27: 00",(((Time()-[Hours]![StartTime])*24*60)*[Personnel]),IIf(Time()>"1 0:27:00"
And
Time()<="13:30: 00",(((Time()-[Hours]![StartTime])*24*60-12)*[Personnel]),IIf(Time()>"1 3:30:00"
And
Time()<="15:27: 00",(((Time()-[Hours]![StartTime])*24*60-42)*[Personnel]),(((((Time()-[Hours]![StartTime])*24)*60)-54)*[Personnel])))))))
here is it simplified.
i have a table which holds the start/end time for each day, the number
of hours for each day and the number of non-productive hours for the
day.
Our day starts at 09:00 and finishes at 18:00 - Time diff 9 hours.
during this time period there is 1 hours worth of breaks making a
working day of 8 hours per person. for this excise lets say there is
only one person. Now that persons day is made up of 2 hours
non-productive work and 6 hours of productive work.
now what i am trying to achieve is to spread a 6 hour productive
working day over a 9 hour shift, now the breaks are not a problem, but
incorporating the non-productive time over the course of the day, is
doing my head in, i cannot just throw it in at the start or end of the
day i need to account for it thru-out the day
any help would be appreciated
2  1539  sm*******@burbi dge.co.uk wrote: Access 2000 question
Hi any help or advise required if possible
i am trying to create a formula for a field. here is what i have
currently
rem:
IIf(Time()<[Hours]![StartTime],MinToTime(([Hours]*60)),MinToTime ((([Hours]*60))-([Hours]![Non-Productive]*60)-(IIf(Time()>"09 :00:00"
And
Time()<="10:27: 00",(((Time()-[Hours]![StartTime])*24*60)*[Personnel]),IIf(Time()>"1 0:27:00"
And
Time()<="13:30: 00",(((Time()-[Hours]![StartTime])*24*60-12)*[Personnel]),IIf(Time()>"1 3:30:00"
And
Time()<="15:27: 00",(((Time()-[Hours]![StartTime])*24*60-42)*[Personnel]),(((((Time()-[Hours]![StartTime])*24)*60)-54)*[Personnel])))))))
here is it simplified.
i have a table which holds the start/end time for each day, the number
of hours for each day and the number of non-productive hours for the
day.
Our day starts at 09:00 and finishes at 18:00 - Time diff 9 hours.
during this time period there is 1 hours worth of breaks making a
working day of 8 hours per person. for this excise lets say there is
only one person. Now that persons day is made up of 2 hours
non-productive work and 6 hours of productive work.
now what i am trying to achieve is to spread a 6 hour productive
working day over a 9 hour shift, now the breaks are not a problem, but
incorporating the non-productive time over the course of the day, is
doing my head in, i cannot just throw it in at the start or end of the
day i need to account for it thru-out the day
any help would be appreciated
Perhaps this will help get you started: http://groups.google.com/group/comp....ed54b162a1aa3c
James A. Fortune CD********@Fort uneJames.com
Interesting site: http://www.doityourself.com
Thanks for your help, however my boss finally got it to work, here is
the formula
IIf(Time()<[Hours]![StartTime],MinToTime([Hours]*60-[Non-Productive]*60),+MinToTime (+[Hours]*60-[Non-Productive]*60-DateDiff("n",[StartTime],Time())*[Personnel]+IIf(Time()>"10 :15:00",IIf(Tim e()<"10:27:00", DateDiff("n","1 0:15:00",Time() ),12),0)*[Personnel]+IIf(Time()>"13 :00:00",IIf(Tim e()<"13:30:00", DateDiff("n","1 3:00:00",Time() ),30),0)*[Personnel]+IIf(Time()>"15 :15:00",IIf(Tim e()<"15:27:00", DateDiff("n","1 5:15:00",Time() ),12),0)*[Personnel]))
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