Hi!
This line wont execute in Windows 2000, even though it worked fine in
Windows XP.
DoCmd.OutputTo acReport, strReportName, acFormatRTF, strRTFName
When debugging all the arguments seem fine. strRTFName has the
location of a directory that exists, strReportName is the name of an
object which indeed exists in the current database. Is there any
reason why this shouldn't work in Win2000?
I'd appreciate any help
Vegard
31  2418 
Vegard Villmones wrote: Hi!
This line wont execute in Windows 2000, even though it worked fine in
Windows XP.
DoCmd.OutputTo acReport, strReportName, acFormatRTF, strRTFName
When debugging all the arguments seem fine. strRTFName has the
location of a directory that exists, strReportName is the name of an
object which indeed exists in the current database. Is there any
reason why this shouldn't work in Win2000?
I'd appreciate any help
Vegard
How is it not working? are you getting any error messages?
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!
No. When I run the debugger it jumps to the line it's supposed to (on
error goto K) and prints my error message. Now you might think I forgot
an exit sub-statement, but I haven't.
Is there any way to get more info on why the error occurs? Guess I'm not
a pro :)
*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it! This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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