Hi all, I'm not sure how to get around this, I was hoping someone
could provide me with some help. Let's take this simple data set of 2
columns in a table:
Tom - id1
Bob - id2
Jane - id1
John - id8
Fred - id2
John - id8
Bob - id1
Using SQL, I'm trying to return the ones that are *not* unique. I
don't really know if Tom is actually id1 or if Jane is. Since they
both share an ID, I want to return them (as the errors!). Since Bob
has 2 different IDs and ID2 can also belong to Fred, I want to return
all of those. (etc). The only one not coming back should be
John-id8, because he's the one with the unique ID (even if he's listed
twice).
These names and IDs are two different columns in the same table, so no
inter-table relationships involved here!
Can anyone possibly offer assistance? Much thanks!
T-McK 3 8027
"Thomas McK" <ed********@yah oo.com> wrote in message
news:85******** *************** **@posting.goog le.com... Hi all, I'm not sure how to get around this, I was hoping someone could provide me with some help. Let's take this simple data set of 2 columns in a table:
Tom - id1 Bob - id2 Jane - id1 John - id8 Fred - id2 John - id8 Bob - id1
Using SQL, I'm trying to return the ones that are *not* unique. I don't really know if Tom is actually id1 or if Jane is. Since they both share an ID, I want to return them (as the errors!). Since Bob has 2 different IDs and ID2 can also belong to Fred, I want to return all of those. (etc). The only one not coming back should be John-id8, because he's the one with the unique ID (even if he's listed twice).
These names and IDs are two different columns in the same table, so no inter-table relationships involved here!
Can anyone possibly offer assistance? Much thanks!
T-McK
We don't have your table and field names, but you should be able to adjust
the following accordingly:
SELECT ConID, ConName FROM tblContacts WHERE ConID IN
(SELECT X.ConID FROM
(SELECT ConID FROM tblContacts GROUP BY ConID, ConName) AS X
GROUP BY X.ConID HAVING Count(*)>1)
ORDER BY ConID, ConName
On 28 Sep 2004 12:39:01 -0700, ed********@yaho o.com (Thomas McK)
wrote: Hi all, I'm not sure how to get around this, I was hoping someone could provide me with some help. Let's take this simple data set of 2 columns in a table:
Tom - id1 Bob - id2 Jane - id1 John - id8 Fred - id2 John - id8 Bob - id1
Using SQL, I'm trying to return the ones that are *not* unique. I don't really know if Tom is actually id1 or if Jane is. Since they both share an ID, I want to return them (as the errors!). Since Bob has 2 different IDs and ID2 can also belong to Fred, I want to return all of those. (etc). The only one not coming back should be John-id8, because he's the one with the unique ID (even if he's listed twice).
These names and IDs are two different columns in the same table, so no inter-table relationships involved here!
Can anyone possibly offer assistance? Much thanks!
T-McK
Hi
Here is a brute-force method, I am sure someone has a simple and or
elegant one!
query2 = SELECT DISTINCT Table2.name, Table2.id FROM Table2;
singleids =
SELECT id FROM Query2 GROUP BY id HAVING Count(Query2.na me)=1;
singlenames =
SELECT name FROM Query2 GROUP BY name HAVING Count(Query2.id )=1;
unique =
SELECT DISTINCT Table2.*
FROM (Table2 INNER JOIN singlenames ON Table2.name = singlenames.nam e)
INNER JOIN singleids ON Table2.id = singleids.id;
David
That was very, very helpful! Both of you presented different ways to
do it, and certainly opened my eyes to new solutions. Thanks!! d.************* **@blueyonder.c o.uk (David Schofield) wrote in message news:<4159e768. 439640759@local host>... On 28 Sep 2004 12:39:01 -0700, ed********@yaho o.com (Thomas McK) wrote:
Hi all, I'm not sure how to get around this, I was hoping someone could provide me with some help. Let's take this simple data set of 2 columns in a table:
Tom - id1 Bob - id2 Jane - id1 John - id8 Fred - id2 John - id8 Bob - id1
Using SQL, I'm trying to return the ones that are *not* unique. I don't really know if Tom is actually id1 or if Jane is. Since they both share an ID, I want to return them (as the errors!). Since Bob has 2 different IDs and ID2 can also belong to Fred, I want to return all of those. (etc). The only one not coming back should be John-id8, because he's the one with the unique ID (even if he's listed twice).
These names and IDs are two different columns in the same table, so no inter-table relationships involved here!
Can anyone possibly offer assistance? Much thanks!
T-McK
Hi Here is a brute-force method, I am sure someone has a simple and or elegant one!
query2 = SELECT DISTINCT Table2.name, Table2.id FROM Table2;
singleids = SELECT id FROM Query2 GROUP BY id HAVING Count(Query2.na me)=1;
singlenames = SELECT name FROM Query2 GROUP BY name HAVING Count(Query2.id )=1;
unique = SELECT DISTINCT Table2.* FROM (Table2 INNER JOIN singlenames ON Table2.name = singlenames.nam e) INNER JOIN singleids ON Table2.id = singleids.id;
David This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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