jython code

[spgreddy]

Hi,

When I execute below program I am getting the below output.

for row in c.fetchall():
        urls=row
        print urls
 

('http://10.136.229.129:7010',)
('http://10.136.229.129:7020',)
('http://10.136.229.129:7030',)
('http://10.136.229.129:7040',)
('http://10.136.229.44:7050',)
('http://10.136.229.44:7060',)
('http://10.136.229.44:7070',)
('http://10.136.229.44:7080',)


but I want to get below output

http://10.136.229.129:7010
http://10.136.229.129:7020
http://10.136.229.129:7030
http://10.136.229.129:7040
http://10.136.229.44:7050
http://10.136.229.44:7060
http://10.136.229.44:7070
http://10.136.229.44:7080

Please let me know how can I achieve this by either python or jython script

Regards
spgreddy

[bvdet]

c.fetchall() returns a list of tuples. To cover the possibility of an empty tuple or tuple with multiple entries:

print "\n".join([",".join(item) for item in c.fetchall()])