Searching the newline charcter using XSLT

[amollokhande1]

Hi,

I am fetching the data from the database and assigning it to the textarea. Before that Xml is loaded with data and then stylesheet gets applied to the xml to generate the html output with textarea with data in it. I want to replace the newline character with '\n' character. I tried to use following psedudo code

:
:
<xsl:when test="contains( $text,' ')">
<xsl:value-of select="substri ng-before($text, ' ')"/>\n<xsl:call-template name="break">
<xsl:with-param name="text" select="substri ng-after($text,' ' )"/>
</xsl:call-template>
</xsl:when>

This did not worked. I have also tried to use '&#xa' instead but that also did not worked.

Can anybody tell me how to search and replace the newline character using xslt?

Regards
Amol Lokhande

[Dormilich]

you could try

<xsl:text>&#10;</xsl:text>

since \n doesn't have any special meaning is xslt.

[Sid Fadnis]

I think both should work

    <xsl:text>&#xD;</xsl:text>
    <xsl:text>
</xsl:text> 

---------------------------------------------
Sample XML FIle
---------------------------------------------

<?xml version="1.0"?>
<root>
<library id="1">
<books>
<book id="1">
    <name>Book 1</name>
    <author>Author A</author>
</book>
<book id="2">
    <name>Book 2</name>
    <author>Author B</author>
</book>
<book id="3">
    <name>Book 3</name>
    <author>Author C</author>
</book>
<book id="4">
    <name>Book 4</name>
    <author>Author A and Author D</author>
</book>
</books>
</library>
</root>

---------------------------------------------
Sample XSL FIle
---------------------------------------------

<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text"/>
<xsl:template match="/">
    <xsl:text>&#xD;</xsl:text>
    <xsl:apply-templates select="root/library[./@id = '1']/books/book"/>
</xsl:template>
<xsl:template match="book">
    <xsl:value-of select="./@id"/>
    <xsl:value-of select="' Title: '"/>
    <xsl:value-of select="name"/>
    <xsl:value-of select="' Author: '"/>
    <xsl:value-of select="author"/>
    <xsl:text>&#xD;</xsl:text>
    <xsl:text>
</xsl:text> 
</xsl:template>
</xsl:stylesheet>

---------------------------------------------
Output (notice two new lines appended after each row)
---------------------------------------------
1 Title: Book 1 Author: Author A


2 Title: Book 2 Author: Author B


3 Title: Book 3 Author: Author C


4 Title: Book 4 Author: Author A and Author D

[Sid Fadnis]

in my post above the browser converted this code

<xsl:text> & # 1 0 ; </xsl:text>

(remove all spaces from abobve)

to

<xsl:text> </xsl:text>

[jkmyoung]

Could try:

<xsl:variable name="newline">
<xsl:text>
</xsl:text>
</xsl:variable>

What is processing the result of the transformation?