xsl:element question

[bklopfen]

I am trying to create XSLT to convert XML like this:

<?xml version="1.0" encoding="UTF-8"?>
<sampledoc>
    <asdf mytoken="name1234">
        <qwer>value1234</qwer>
    </asdf>
    <asdf mytoken="name6789">
        <qwer>value6789</qwer>
    </asdf>
</sampledoc>
 

Into this:

<?xml version="1.0" encoding="UTF-8"?>
<myroot>
    <name1234>value1234</name1234>
    <name6789>value6789</name6789>
</myroot>
 

This is what I thought would work using xsl:element tags:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" encoding="UTF-8" indent="yes" />
 
    <xsl:template match="asdf">
        <xsl.element name="{@mytoken}">
            <xsl:value-of select="qwer"/>
        </xsl.element>
    </xsl:template>
 
    <xsl:template match="sampledoc">
    <myroot>
        <xsl:apply-templates/>
    </myroot>
    </xsl:template>
</xsl:stylesheet>
 

But the results I am getting is this (the xsl.element is carrying over instead of executing?):

<?xml version="1.0" encoding="UTF-8"?>
<myroot>
    <xsl.element name="name1234">value1234</xsl.element>
    <xsl.element name="name6789">value6789</xsl.element>
</myroot>
 

What am I missing to make this behave as I want? I haven't found any clues in my search of XSLT internet references and Q&A...

Thanks,
Bryan

[bklopfen]

Well, all I had to do was post that to find the issue!!

If I had really typed xsl:element instead of xsl.element (colon instead of period) it would have worked the first time!

Thanks for being a forum where someone can ask questions like this!
Bryan

[dorinbogdan]

You're always welcome.

Glad to see you getting the answer.

God bless you,
Dorin.

[Badrimahesh]

hi do
i want help from pls help me, pls find the problem below

if i use like

select xmlelement (name ,xmlelemet(sub ,xmlattribute (sno)))
from emp;

out put

<name><sub sno = 123 </suba></name>

i want like

<name><sub sno = 123 /></name>