Setting Pixel Color in VB 2005

[fripper]

I am using VB 2005 and want to generate a graphic in a picture box control
where the color of each pixel is determined by particular values calculated
for each pixel. These values are manipulated in such a way that I come up
with three values (each in the range 0-155) and I want to use these for the
RGB values of the color of the associated pixel. My question is: In VB
2005 how do I set a particular pixel to a color with a given set of RGB
values? In VB 6 I used the PSET function but it is not available in VB
2005.

Thanks.

[Herfried K. Wagner [MVP]]

"fripper" <yo***@indiana.edu> schrieb:

I am using VB 2005 and want to generate a graphic in a picture box control
where the color of each pixel is determined by particular values calculated
for each pixel. These values are manipulated in such a way that I come up
with three values (each in the range 0-155) and I want to use these for the
RGB values of the color of the associated pixel. My question is: In VB
2005 how do I set a particular pixel to a color with a given set of RGB
values? In VB 6 I used the PSET function but it is not available in VB
2005.

Create a new 'Bitmap' object of appropriate size. Then you can use its
'SetPixel' method to change the color of a certain pixel. The bitmap object
can be assigned to a picturebox' 'Image' property.

--
M S Herfried K. Wagner
M V P <URL:http://dotnet.mvps.org/>
V B <URL:http://classicvb.org/petition/>

[Chris]

fripper wrote:

I am using VB 2005 and want to generate a graphic in a picture box control
where the color of each pixel is determined by particular values calculated
for each pixel. These values are manipulated in such a way that I come up
with three values (each in the range 0-155) and I want to use these for the
RGB values of the color of the associated pixel. My question is: In VB
2005 how do I set a particular pixel to a color with a given set of RGB
values? In VB 6 I used the PSET function but it is not available in VB
2005.

Thanks.

Dim C as Color = Color.FromArgb(IntAlpha, IntRed, IntGreen, IntBlue)

Chris