VB.NET TreeView move to next node

[adh]

How do you move by program to the next node of a treeview (NextButton)?
Thanks

[Peter Huang [MSFT]]

Hi

1. We can use the SelectedNode to get the current selected node
2. We use the NextNode Property to retrieve the next node
3. We set the NextNode to the SelectedNode, so that the "NextNode" will be
the current selected node.
e.,g.
Me.TreeView1.SelectedNode = Me.TreeView1.SelectedNode.NextNode
Best regards,

Peter Huang
Microsoft Online Partner Support

Get Secure! - www.microsoft.com/security
This posting is provided "AS IS" with no warranties, and confers no rights.

[adh]

Thanks for the prompt reply.
My Nodes are sub nodes of Node(0) so
.Nodes(0).NextNode
Did not work for me (it jumps to Node(1) not to the next sub node)
2)
.NextNode does not check the end of nodes. so what I'm using is:
With stvView.trvViews
If .Nodes(0).LastNode.Index = .SelectedNode.Index Then
.SelectedNode = .Nodes(0).Nodes(0)
Else
.SelectedNode = .Nodes(0).Nodes(.SelectedNode.Index + 1)
End If
End With

????

Thanks, adh

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[Robin Tucker]

Sure that will work, but you will screw up when you get to the end of a
branch and want to come back down the other side (if you see what I mean).

A proper traversal of a tree, in order, requires a stack (or recursion).
Your code below will traverse from the current position to the nearest leaf.

"adh" <ad*@devx.com> wrote in message
news:e4**************@TK2MSFTNGP10.phx.gbl...

Thanks for the prompt reply.
My Nodes are sub nodes of Node(0) so
Nodes(0).NextNode
Did not work for me (it jumps to Node(1) not to the next sub node)
2)
NextNode does not check the end of nodes. so what I'm using is:
With stvView.trvViews
If .Nodes(0).LastNode.Index = .SelectedNode.Index Then
.SelectedNode = .Nodes(0).Nodes(0)
Else
.SelectedNode = .Nodes(0).Nodes(.SelectedNode.Index + 1)
End If
End With

????

Thanks, adh

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[adh]

OK. Got it.
Thanks, adh

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[Peter Huang [MSFT]]

Hi

I agree with Robin's suggestion.
If you wants to traverse a tree strcture of treenodes, you need to use
recursion or stack.

Best regards,

Peter Huang
Microsoft Online Partner Support

Get Secure! - www.microsoft.com/security
This posting is provided "AS IS" with no warranties, and confers no rights.