Wrong value using val(textbox.text)

[Drygast]

I get the value that doesn't add up correct.

I have 2 textboxes where I enter numbers, I then calculate them and present
them as a reslut in a 3rd
textbox, however when the result is calculated it won't calculate the
correct value.
For instance when the value is 75,25 the code interprets it as 75.

The code:
lblSumma2.Text = Val(lblSumma2.Text) + ((txtAntal.Text) * myMinutNetto) +
myFastNetto

The problem is the val(lblsumma2.text), it skips the decimals, how can I
change this to use the actual number?
(lblSumma2.text will show the correct value, the problem is just when using
the val()-option)

Regards
/Drygast

[Herfried K. Wagner [MVP]]

* "Drygast" <dr*****@hotmail.com> scripsit:

I have 2 textboxes where I enter numbers, I then calculate them and present
them as a reslut in a 3rd
textbox, however when the result is calculated it won't calculate the
correct value.
For instance when the value is 75,25 the code interprets it as 75.

The code:
lblSumma2.Text = Val(lblSumma2.Text) + ((txtAntal.Text) * myMinutNetto) +
myFastNetto

The problem is the val(lblsumma2.text), it skips the decimals, how can I
change this to use the actual number?
(lblSumma2.text will show the correct value, the problem is just when using
the val()-option)

<msdn>
Note The Val function recognizes only the period (.) as a valid decimal separator. When different decimal separators are used, as in international applications, use CDbl or CInt instead to convert a string to a number.
</msdn>

You can use 'Double.Parse' to parse the value of the string.

--
Herfried K. Wagner
MVP · VB Classic, VB.NET
<http://www.mvps.org/dotnet>

[Drygast]

Lightning fast repsonse!

Thanks I'll try yout suggestion.

I also tried a "short-cut" using
val(lblSumma2.text.Replace(",", "."))

and that worked for me.

Regards

/Drygast

"Herfried K. Wagner [MVP]" <hi***************@gmx.at> wrote in message
news:bm************@ID-208219.news.uni-berlin.de...

* "Drygast" <dr*****@hotmail.com> scripsit:

I have 2 textboxes where I enter numbers, I then calculate them and present them as a reslut in a 3rd
textbox, however when the result is calculated it won't calculate the
correct value.
For instance when the value is 75,25 the code interprets it as 75.

The code:
lblSumma2.Text = Val(lblSumma2.Text) + ((txtAntal.Text) * myMinutNetto) + myFastNetto

The problem is the val(lblsumma2.text), it skips the decimals, how can I
change this to use the actual number?
(lblSumma2.text will show the correct value, the problem is just when using the val()-option)
<msdn>
Note The Val function recognizes only the period (.) as a valid decimal

separator. When different decimal separators are used, as in international
applications, use CDbl or CInt instead to convert a string to a number. </msdn>

You can use 'Double.Parse' to parse the value of the string.

--
Herfried K. Wagner
MVP · VB Classic, VB.NET
<http://www.mvps.org/dotnet>

[Herfried K. Wagner [MVP]]

* "Drygast" <dr*****@hotmail.com> scripsit:

Lightning fast repsonse!

Thanks I'll try yout suggestion.

I also tried a "short-cut" using
val(lblSumma2.text.Replace(",", "."))

and that worked for me.

Notice that this will not work on every systems as expected because
different languages/cultures use different characters as decimal comma.

--
Herfried K. Wagner
MVP · VB Classic, VB.NET
<http://www.mvps.org/dotnet>

[Armin Zingler]

"Drygast" <dr*****@hotmail.com> schrieb

I get the value that doesn't add up correct.

I have 2 textboxes where I enter numbers, I then calculate them and
present them as a reslut in a 3rd
textbox, however when the result is calculated it won't calculate
the correct value.
For instance when the value is 75,25 the code interprets it as 75.

The code:
lblSumma2.Text = Val(lblSumma2.Text) + ((txtAntal.Text) *
myMinutNetto) + myFastNetto

The problem is the val(lblsumma2.text), it skips the decimals, how
can I change this to use the actual number?
Don't use Val. It expects the "." as decimal separator. Use Decimal.Parse,
Double.Parse, CSng, CDec, CDbl, ...
(lblSumma2.text will show the correct value, the problem is just when
using the val()-option)

--
Armin