I'm about to convert to string and use regex, but I thought there must be
something I'm missing here that already exists.
Bob
15  20103 
use the re expression in a Format
MyStr = Format(5459.4, "##,##0.00" ) ' Returns "5,459.40".
--
Regards - One Handed Man
Author : Fish .NET & Keep .NET
=============== =============== ===========
This posting is provided "AS IS" with no warranties,
and confers no rights.
"Bob" <no*****@nospam .net> wrote in message
news:eV******** *******@tk2msft ngp13.phx.gbl.. . I'm about to convert to string and use regex, but I thought there must be
something I'm missing here that already exists.
Bob
Please explain to me how this can be applied as a general solution.
"One Handed Man" <te************ *************** @BTOpenworld.co m> wrote in
message news:%2******** ********@tk2msf tngp13.phx.gbl. .. use the re expression in a Format
MyStr = Format(5459.4, "##,##0.00" ) ' Returns "5,459.40".
--
Regards - One Handed Man
Author : Fish .NET & Keep .NET
=============== =============== ===========
This posting is provided "AS IS" with no warranties,
and confers no rights.
"Bob" <no*****@nospam .net> schrieb I'm about to convert to string and use regex, but I thought there
must be something I'm missing here that already exists.
Could you please give us an example of which values have to be formatted
how?
--
Armin
Okay, I think I got it.
Function RemoveTrialingZ eros(ByVal dec As Decimal) As Decimal
Return CDec(CSng(dec))
End Function
Bob
"Bob" <no*****@nospam .net> wrote in message
news:eV******** *******@tk2msft ngp13.phx.gbl.. . I'm about to convert to string and use regex, but I thought there must be
something I'm missing here that already exists.
Bob
324.0000 -- 324
324.0100 -- 324.01
324.0001 -- 324.0001
"Armin Zingler" <az*******@free net.de> wrote in message
news:OX******** ******@TK2MSFTN GP09.phx.gbl... "Bob" <no*****@nospam .net> schrieb I'm about to convert to string and use regex, but I thought there
must be something I'm missing here that already exists.
Could you please give us an example of which values have to be formatted
how?
--
Armin
"Bob" <no*****@nospam .net> schrieb 324.0000 -- 324
324.0100 -- 324.01
324.0001 -- 324.0001
The type of the values in the left column is not Decimal, it is String.
There are no trailing zeros in Decimals. The default behavior is that there
are *no* trailing zeros when converting a Decimal to a String, that's why I
don't understand the question:
Dim d As Decimal
d = 324D
MsgBox(d.ToStri ng) 'returns "324"
d = 324.01D
MsgBox(d.ToStri ng) 'returns "324.01"
d = 324.0001D
MsgBox(d.ToStri ng) 'returns "324.0001"
--
Armin
Hello,
"Bob" <no*****@nospam .net> schrieb: 324.0000 -- 324
324.0100 -- 324.01
324.0001 -- 324.0001
Is that contained in a string like "bla foo baz 342.0000 bar baz foo 234.02
bla"?
Regards,
Herfried K. Wagner
--
MVP · VB Classic, VB.NET http://www.mvps.org/dotnet
Okay, you got me. It's for when I'm displaying the decimal value as a string. I
have some data being returned that comes back as datatype decimal that always
trails with 4 zeros even if the value is integer. I just wanted to chop off the
unnecessary zeros and thought a ...
oh hell.
Here it is.
Dim foo As Decimal = CDec("1.0100")
MsgBox(Format(f oo, "#.####"))
thanks for kicking my brain into gear.
Bob
"Armin Zingler" <az*******@free net.de> wrote in message
news:%2******** ********@TK2MSF TNGP09.phx.gbl. .. "Bob" <no*****@nospam .net> schrieb 324.0000 -- 324
324.0100 -- 324.01
324.0001 -- 324.0001
The type of the values in the left column is not Decimal, it is String.
There are no trailing zeros in Decimals. The default behavior is that there
are *no* trailing zeros when converting a Decimal to a String, that's why I
don't understand the question:
Dim d As Decimal
d = 324D
MsgBox(d.ToStri ng) 'returns "324"
d = 324.01D
MsgBox(d.ToStri ng) 'returns "324.01"
d = 324.0001D
MsgBox(d.ToStri ng) 'returns "324.0001"
--
Armin
Sorry i didnt get back sooner, bu you saw the light anyway.
Well done
--
Regards - One Handed Man
Author : Fish .NET & Keep .NET
=============== =============== ===========
This posting is provided "AS IS" with no warranties,
and confers no rights.
"Bob" <no*****@nospam .net> wrote in message
news:e6******** ******@tk2msftn gp13.phx.gbl... Okay, you got me. It's for when I'm displaying the decimal value as a
string. I have some data being returned that comes back as datatype decimal that
always trails with 4 zeros even if the value is integer. I just wanted to chop
off the unnecessary zeros and thought a ...
oh hell.
Here it is.
Dim foo As Decimal = CDec("1.0100")
MsgBox(Format(f oo, "#.####"))
thanks for kicking my brain into gear.
Bob
"Armin Zingler" <az*******@free net.de> wrote in message
news:%2******** ********@TK2MSF TNGP09.phx.gbl. .. "Bob" <no*****@nospam .net> schrieb 324.0000 -- 324
324.0100 -- 324.01
324.0001 -- 324.0001
The type of the values in the left column is not Decimal, it is String.
There are no trailing zeros in Decimals. The default behavior is that
there are *no* trailing zeros when converting a Decimal to a String, that's
why I don't understand the question:
Dim d As Decimal
d = 324D
MsgBox(d.ToStri ng) 'returns "324"
d = 324.01D
MsgBox(d.ToStri ng) 'returns "324.01"
d = 324.0001D
MsgBox(d.ToStri ng) 'returns "324.0001"
--
Armin This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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