This query must be easy but need help

[gwhite1]

I have a table like this:

Name, SSN
Joe Smith, 1111
Tom Why, 2222
Larry Sam, 3333
Paul Tom, 4444
Steve bob, 1111

I want a query to pull off

Joe Smith, 1111
Steve bob, 1111

because someone accidently put in two different names with the same
SSN. There should only be one 1111 in the SSN field in the whole
database. I want to pull the duplicate SSN with the name. How can one
query do this. I can write a VB program to do it but I think a query
should work.

I know how to do this:

SELECT SSN, COUNT(*) AS cnt
FROM test
GROUP BY fSSN
HAVING (COUNT(*) > 1)

to find the duplicate SSN but I need the name listed with the SSN also.
Any help?? Thanks!!

Sheila

[MC]

try this one:

select test.Name, test.SSN
from
test
inner join (select SSN from test group by SSN having count(*)>1) t2 on
test.ssn = t2.ssn

<gw*****@kc.rr.com> wrote in message
news:11**********************@g49g2000cwa.googlegr oups.com...

I have a table like this:

Name, SSN
Joe Smith, 1111
Tom Why, 2222
Larry Sam, 3333
Paul Tom, 4444
Steve bob, 1111

I want a query to pull off

Joe Smith, 1111
Steve bob, 1111

because someone accidently put in two different names with the same
SSN. There should only be one 1111 in the SSN field in the whole
database. I want to pull the duplicate SSN with the name. How can one
query do this. I can write a VB program to do it but I think a query
should work.

I know how to do this:

SELECT SSN, COUNT(*) AS cnt
FROM test
GROUP BY fSSN
HAVING (COUNT(*) > 1)

to find the duplicate SSN but I need the name listed with the SSN also.
Any help?? Thanks!!

Sheila

[gwhite1]

It worked perfect! Thanks for your help!!

[--CELKO--]

Don't forget to add a constraint to the table so this will not happen
again.