My SELECT query returns a data set, one column of which contains a set
of values corresponding to the same date. I.e. for each date in column
"Date", I have a set of numbers in column "Numbers". However, I am
only interested in getting the largest value in column "Numbers"
corresponding to each value in column "Date". How do I do that?
Thanks,
Marco
2  1290  md***@hotmail.c om (Marco) wrote in news:e5f1d809.0 411190312.c9f8b 07
@posting.google .com: My SELECT query returns a data set, one column of which contains a set
of values corresponding to the same date. I.e. for each date in column
"Date", I have a set of numbers in column "Numbers". However, I am
only interested in getting the largest value in column "Numbers"
corresponding to each value in column "Date". How do I do that?
Thanks,
Marco
SELECT "Date", MAX("Numbers")A S "Largest number"
FROM sometable
GROUP BY "Date"
Marco wrote: My SELECT query returns a data set, one column of which contains a set
of values corresponding to the same date. I.e. for each date in column
"Date", I have a set of numbers in column "Numbers". However, I am
only interested in getting the largest value in column "Numbers"
corresponding to each value in column "Date". How do I do that?
Thanks,
Marco
Look up MAX and GROUP BY. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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