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Recursive Stored Procedure

3 New Member
Hello Guys,

I am developing a web application to manage Active Directory resources, and one of my tasks is to map Organizational Units hierarchy into a SQL Server database. Let's suppose that I have the following OU hierarchy in my Active Direcoty:

1. NewYork
1.1 HR_Department
1.1.1 Computers
1.1.2 Users
1.2 SALES_Departmen t
1.1.1 Computers
1.1.2 Users
1.3 So on.....
2. Chicago
2.1 HR_Department
1.1.1 Computers
1.1.2 Users
2.2 SALES_Departmen t
2.1.1 Computers
2.1.2 Users
2.3 So on....

I designed the following table into SQL Server in order to reach the AD hierarchy:

OUId INT
// Just an integer ID to identify the row.

OUName VARCHAR(50)
// Name of OU that comes from AD.

ParentOUId INT
// Id of the parent OU to create as many levels as necessary.

The idea is to create a recursive table to store the hierarchy in a flexible way that there won't be any limitations in terms of creating as many sub OU as necessary. At this point goes my issue: I am having problems to create a store procedure to return whether a OU already exists or not.

Unfortunately Active Directory does not provide me a property that indicates who is parent OU. I can only identify the object structure by the distinguishedNa me property, which acording to my example returns something like:

OU=Computers,OU =HR_Deparment, OU=NewYork, DC=....

From this string, I convert it to an array:

[0] Computers
[1] HR_Department
[2] NewYork

From now on, I am stuck. I don't know how to create a recursive procedure or function in the context to return and create the AD Hierarchy.


Could anyone help with it?

Thank you very much for you attention!
Jul 18 '08 #1
3 2382
ck9663
2,878 Recognized Expert Specialist
I'd say use XML


-- CK
Jul 18 '08 #2
fabiomoggi
3 New Member
Hi,

Thank you for the answer!

I don't know how to approach it using XML.

Could you help me on how to start it?
Jul 18 '08 #3
Delerna
1,134 Recognized Expert Top Contributor
Here is a question similar to yours that you might find helpful.
Jul 18 '08 #4

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