I am getting 2 resultsets depending on conditon, In the second
conditon i am getting the above error could anyone help me..........
CREATE proc sp_count_AllNew sPapers
@CustomerId int
as
declare @NewsId int
set @NewsId = (select NewsDelId from NewsDelivery where
CustomerId=@Cus tomerId )
if not exists(select CustomerId from NewsDelivery where
NewsPapersId=@N ewsId)
begin
select count( NewsPapersId) from NewsPapers
end
if exists(select CustomerId from NewsDelivery where
NewsPapersId=@N ewsId)
begin
select count(NewsDelId ) from NewsDelivery where
Customerid=@Cus tomerid
end
GO 3 31426
On 20 Apr 2004 08:26:03 -0700, Nachi wrote: I am getting 2 resultsets depending on conditon, In the second conditon i am getting the above error could anyone help me..........
CREATE proc sp_count_AllNew sPapers @CustomerId int as declare @NewsId int set @NewsId = (select NewsDelId from NewsDelivery where CustomerId=@Cu stomerId ) if not exists(select CustomerId from NewsDelivery where NewsPapersId=@ NewsId)
begin select count( NewsPapersId) from NewsPapers end if exists(select CustomerId from NewsDelivery where NewsPapersId=@ NewsId)
begin select count(NewsDelId ) from NewsDelivery where Customerid=@Cu stomerid
end GO
This is the cause of your problem:
set @NewsId = (select NewsDelId from NewsDelivery where
CustomerId=@Cus tomerId )
There are apparently at least two rows in NewsDelivery that satisfy
the condition CustomerId = @CustomerID. The value for @NewsID can only
be taken from one of these rows, but which one? You didn't tell SQL
Server how to choose, so SQL Server throws an error message.
Apart from this, I fail to see the logic of what you're doing, but I
think it can be done simpler. Can you explain what you try to achieve?
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address)
Hugo Kornelis <hugo@pe_NO_rFa ct.in_SPAM_fo> wrote in message news:<a4******* *************** **********@4ax. com>... On 20 Apr 2004 08:26:03 -0700, Nachi wrote:
I am getting 2 resultsets depending on conditon, In the second conditon i am getting the above error could anyone help me..........
CREATE proc sp_count_AllNew sPapers @CustomerId int as declare @NewsId int set @NewsId = (select NewsDelId from NewsDelivery where CustomerId=@Cu stomerId ) if not exists(select CustomerId from NewsDelivery where NewsPapersId=@ NewsId)
begin select count( NewsPapersId) from NewsPapers end if exists(select CustomerId from NewsDelivery where NewsPapersId=@ NewsId)
begin select count(NewsDelId ) from NewsDelivery where Customerid=@Cu stomerid
end GO
This is the cause of your problem:
set @NewsId = (select NewsDelId from NewsDelivery where CustomerId=@Cus tomerId )
There are apparently at least two rows in NewsDelivery that satisfy the condition CustomerId = @CustomerID. The value for @NewsID can only be taken from one of these rows, but which one? You didn't tell SQL Server how to choose, so SQL Server throws an error message.
Apart from this, I fail to see the logic of what you're doing, but I think it can be done simpler. Can you explain what you try to achieve?
Best, Hugo
Hi Guys,
Thanks for kind Help....
Infact i have solved the problem by rewriting the procedure
CREATE proc sp_count_AllNew sPapers
@CustomerId int
as
declare @flag int
if exists (select CustomerId from NewsDelivery where CustomerId=@Cus tomerId )
begin
set @flag=0
end
else
begin
set @flag=1
end
if @flag=1
begin
select count( NewsPapersId) from NewsPapers
end
if @flag=0
begin
select count(NewsDelId ) from NewsDelivery where Customerid=@Cus tomerid
end
GO
On 21 Apr 2004 01:06:23 -0700, Nachi wrote: Infact i have solved the problem by rewriting the procedure
(snip)
Hi Nachi,
Why make it more complex than necessary? The code in David Portas'
first message in this discussion is completely equivalent to your
code, but a lot shorter and easier to maintain.
(David's second suggestion will work as well, but uses some tricks
that not all SQL programmers will be able to understand - this might
make future maintenance more costly)
Best, Hugo
--
(Remove _NO_ and _SPAM_ to get my e-mail address) This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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I know that i am getting more then one value in the second condition
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