How to Modify the XML segment using Python?

[roberttonafelix]

Hi Friends,

i have an xml file which has some data as below...

<ZACGPIAD SEGMENT="1">
<IDENTIFIER>D000</IDENTIFIER>
<CUST_DEL_NO/>
<CUST_DEL_DATE/>
<TRUCKNO/>
<DRIVERNAME/>
<DRIVERID/>
<RESPONS_OFF/>
<CONFIRM_DATE>$&gt;ñô«xr</CONFIRM_DATE>
<SERIAL_NO>9</SERIAL_NO>
<SERIAL_CHAR/>
<DEL_INFO1/>
<QTY>0</QTY>
<DEL_INFO2/>
<QTY>0</QTY>
<DEL_INFO3/>
<QTY>0</QTY>
<TRANS_COMPANY>0</TRANS_COMPANY>
</ZACGPIAD>

this segment is need to be changed as shown below...

<ZACGPIADD SEGMENT="1">
<IDENTIFIER>D000</IDENTIFIER>
<CUST_DEL_NO/>
<CUST_DEL_DATE/>
<TRUCKNO/>
<DRIVERNAME/>
<DRIVERID/>
<RESPONS_OFF/>
<CONFIRM_DATE>$&gt;ñô«xr</CONFIRM_DATE>
<SERIAL_NO>9</SERIAL_NO>
<SERIAL_CHAR/>
<DEL_INFO1/>
<QTY1>0</QTY1>
<DEL_INFO2/>
<QTY2>0</QTY2>
<DEL_INFO3/>
<QTY3>0</QTY3>
<TRANS_COMPANY>0</TRANS_COMPANY>
</ZACGPIADD>

i can able to change the segment name but that <QTY> tag i dont have any idea that how to make this using python...

Kindly guide me if it is possible to do...

Thanks in advance,

Robert.J

[bvdet]

Do you want to change the text node value enclosed by a certain tag such as "QTY1"?

[bvdet]

Assuming your answer to my question is in the affirmative, given a parent node "parent", change the following text node to the value "text".

    def setTextElem(self, parent, text):
        '''Set the first child text element data of parent element. Parent
        and child must be of the form "<head_diam>1.375</head_diam>".'''
        success = False
        for n in parent.childNodes:
            # TEXT_NODE - 3
            if n.nodeType == 3:
                n.data = text
                success = True
        return success

The above is a method of an XML parser class. This only changes the document object in memory - you will need to write the document to disc to make the change permanent.

[roberttonafelix]

thanks for the reply....

i need to change that <QTY> tag to <QTY1>,<QTY2>,<QTY3>....

[bvdet]

That's a bit more involved. I'm not an XML expert, so there may be a better way. Create a new node element with the name you want and child text node. Get the parent node and the node you want to replace and apply xml doc method replaceChild. Following is an example:

Parser is an xml parser class.

>>> a = Parser("test.xml")
>>> print a.backToXML()
<?xml version="1.0" ?>
<person_details>
  <person>
    <name>Mary</name>
    <location> loc1 </location>
  </person>
</person_details>
>>> n = a.doc.getElementsByTagName("name")[0]
>>> n1 = a.doc.getElementsByTagName("person")[0]
>>> new = a.doc.createElement("name1")
>>> new.appendChild(a.doc.createTextNode("XYZ"))
<DOM Text node "'XYZ'">
>>> n1.replaceChild(new, n)
<DOM Element: name at 0x610c2c8>
>>> print a.backToXML()
<?xml version="1.0" ?>
<person_details>
  <person>
    <name1>XYZ</name1>
    <location> loc1 </location>
  </person>
</person_details>
>>> 

[roberttonafelix]

thanks for the reply dude....

but i complete myself using replace....

here is the code which i created....

import os, glob
import time
from datetime import datetime
now=datetime.now()
filepath = "*****************"
os.chdir(filepath)
for files in glob.glob("*.*"):
    r0=now.strftime("%Y/%m/%d-%H:%M:%S")
    curdate=now.strftime("%d-%m-%Y")
    filename=filepath+files
    file1 = open(filename,'r')
    file3=str(file1.read())
    file2 = open("*********"+files,'w')
    string0=file3.replace('<ZACGPIAD SEGMENT="1">','<ZACGPIADD SEGMENT="1">')
    string1=string0.replace('</ZACGPIAD>','</ZACGPIADD>')
    string2=string1.replace('<QTY>','<QTY1>', 1)
    string3=string2.replace('</QTY>','</QTY1>', 1)
    string4=string3.replace('<QTY>','<QTY2>', 1)
    string5=string4.replace('</QTY>','</QTY2>', 1)
    string6=string5.replace('<QTY>','<QTY3>', 1)
    string7=string6.replace('</QTY>','</QTY3>', 1)
    file2.write(string7)
    print files + " Done"
    file2.close()
    filename1=curdate+"_"+"invoicefiles.txt"
    log=file("D:\\Invoice_transfer\\Log\\"+filename1,"a+")
    print >> log,"File name: "+ filename +" Processed time: "+r0
    log.close()
else:
    print "No files found"

[bvdet]

roberttonafelix,

Whatever works for you! Working with text files, str replace would typically be the way to do it. I would prefer an XML parse solution when working with XML though.