How to count letters in a text file?

[nervusvagus]

Following is a code that counts the number of letters in a text file named "alice_in_wonderland.txt"
So far I only have text: aaaaa bbbb cccc
in the text file:

# countletters.py
 
def display(i):
    if i == 10: return 'LF'
    if i == 13: return 'CR'
    if i == 32: return 'SPACE'
    return chr(i)
 
infile = open('alice_in_wonderland.txt', 'r')
text = infile.read()
infile.close
 
counts = 128* [0]
for letter in text:
    counts[ord(letter)]+=1
outfile =open('alice_counts.dat','w')
outfile.write("-12s%s\n" % ("Character","Count"))
outfile.write("====================\n")
for i in range(len(counts)):
        if counts[i]:
            outfile.write("%-12s%d\n" % (display(i), counts[i]))
outfile.close()
 

When I run this code I get the error:

Traceback (most recent call last):
  File "countletters.py", line 15, in <module>
    counts[ord(letter)]+=1
IndexError: list index out of range
 

Even though this example is straight out of the book How to Think Like a Computer Scientist Learning with Python 2nd Edition. Could someone help me find what is wrong with this code?

UPDATE:
When I run the code with the alice_in_wonderland.txt text file provided in this location: http://openbookproject.net/thinkcs/p...sh2e/ch10.html I get a different error:

  File "countletters.py", line 18, in <module>
    outfile.write("-12s%s\n" % ("Character","Count"))
TypeError: not all arguments converted during string formatting
 

[nervusvagus]

This seems to work now with the given text file and the given code, with no apparent reason. Not sure why I was getting the errors above.

[vijaya raghavan]

U missed % symbol before "-12s%s\n" it should be like "%-12s%s\n"

See The Reason is.. U are passing two arguments for writing it, As the % is not there it considered as string and so only one argument get converted to actual value.. and another one not converted...
In python u will get meaningful error.. try understand the error .. u can solve anything...