Re: How to delete a last character from a string

[Derek Martin]

On Fri, Aug 29, 2008 at 07:28:40PM +0100, du**********@gmail.com wrote:

dirListFinal = []
for item in dirList:
print item
if item.endswith('\\') == True:

if item[-1] == '\\':

--
Derek D. Martin
http://www.pizzashack.org/
GPG Key ID: 0x81CFE75D
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[Steven D'Aprano]

On Fri, 29 Aug 2008 14:46:53 -0400, Derek Martin wrote:

On Fri, Aug 29, 2008 at 07:28:40PM +0100, du**********@gmail.com wrote:

>dirListFinal = []
for item in dirList:
print item
if item.endswith('\\') == True:

if item[-1] == '\\':

Which will fail badly if item is the empty string.
Rajat, rather than trying to invent your own code to join directory
paths, you should use the os.path module:

>>import os
os.path.join('/dir', 'x', 'y', 'z', 'file.txt')

'/dir/x/y/z/file.txt'

>>os.path.split('/a/b/c/d/file.txt')

('/a/b/c/d', 'file.txt')
--
Steven

[dudeja.rajat]

On Fri, Aug 29, 2008 at 8:37 PM, Steven D'Aprano
<st***@remove-this-cybersource.com.auwrote:

On Fri, 29 Aug 2008 14:46:53 -0400, Derek Martin wrote:

>On Fri, Aug 29, 2008 at 07:28:40PM +0100, du**********@gmail.com wrote:

>>dirListFinal = []
for item in dirList:
print item
if item.endswith('\\') == True:

if item[-1] == '\\':

Which will fail badly if item is the empty string.
Rajat, rather than trying to invent your own code to join directory
paths, you should use the os.path module:

>>>import os
os.path.join('/dir', 'x', 'y', 'z', 'file.txt')

'/dir/x/y/z/file.txt'

>>>os.path.split('/a/b/c/d/file.txt')

('/a/b/c/d', 'file.txt')
--
Steven
--
http://mail.python.org/mailman/listinfo/python-list

Steven, Thanks so much.
I just found out that I unknowingly searching for something else i.e.
/ rather than \
Just corrected this mistake and fixed it.
--
Regrads,
Rajat

[Derek Martin]

On Fri, Aug 29, 2008 at 07:37:50PM +0000, Steven D'Aprano wrote:

On Fri, 29 Aug 2008 14:46:53 -0400, Derek Martin wrote:

On Fri, Aug 29, 2008 at 07:28:40PM +0100, du**********@gmail.com wrote:

dirListFinal = []
for item in dirList:
print item
if item.endswith('\\') == True:

if item[-1] == '\\':

Which will fail badly if item is the empty string.

Sure. I made 2 assumptions:

1. The OP didn't say how endswith() was failing. My assumption was it
was missing from his version of python (i.e. he's using a version that
predates the feature). I have no idea if that's possible or not...
I've used python 2.4 almost exclusively. I've run into a number of
cases where some clever trick I found on-line didn't work because it
was new in Python 2.5 (or whatever), so it was easy for me to lazily
assume that it could be the case here.

2. If his particular use case didn't exclude the possibility of an
empty string, he'd be smart enough to check that first, or wrap it in
a try block.

Rajat, rather than trying to invent your own code to join directory
paths, you should use the os.path module:

>import os
os.path.join('/dir', 'x', 'y', 'z', 'file.txt')

I agree completely, though I do find that there's one thing missing
from this module's support, which your example illustrates nicely: a
way to find out what the root of the current filesystem is (for some
definition of current which I will let the reader figure out). You
explicitly wrote '/dir', which would likely be wrong on non-Unix OSes,
though IIRC it might work anyway, depending on your particular
environment (e.g. cygwin).

I usually end up doing this via the following function:

def _get_path_root(path):
'''recursive algorithm to determine the name of the root of the file
system in (hopefully) an os-independent way'''

if os.path.dirname(path) == path:
return path
return _get_path_root(os.path.dirname(path))

You can, depending on your needs, either pass it the absolute path of
your script, or the absolute path of your data file(s). For the sake
of performance, I get the real absoulte path outside function:

x = _get_path_root(os.path.realpath(foo))

--
Derek D. Martin
http://www.pizzashack.org/
GPG Key ID: 0x81CFE75D
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