Can anyone suggest a date peocedure...

[RLV]

I'd like to find a simple... (I'm a simple person) procedure to
subtract a numerical number from a six char date string
YYYYMMDD and then convert back to a new date string.

I'm sure there's a way to do it, but the date modules haven't been
much help.

TIA
Ron

[Gary Herron]

RLV wrote:

I'd like to find a simple... (I'm a simple person) procedure to
subtract a numerical number from a six char date string
YYYYMMDD and then convert back to a new date string.

I'm sure there's a way to do it, but the date modules haven't been
much help.

TIA
Ron

--
http://mail.python.org/mailman/listinfo/python-list

The datetime module has what you need.

It has methods (with examples) on building a datetime object from a
string, and it has a object named timedelta, and the ability to subtract
a timedelta from a time.

For instance, the time right now and the time exactly one day ago:

>>from datetime import *
datetime.today()

datetime.datetime(2008, 7, 10, 13, 38, 48, 279539)

>>datetime.today()-timedelta(1)

datetime.datetime(2008, 7, 9, 13, 38, 50, 939580)
Gary Herron

[RV]

On Thu, 10 Jul 2008 13:39:29 -0700, Gary Herron
<gh*****@islandtraining.comwrote:

>The datetime module has what you need.

It has methods (with examples) on building a datetime object from a
string, and it has a object named timedelta, and the ability to subtract
a timedelta from a time.

For instance, the time right now and the time exactly one day ago:

>from datetime import *
datetime.today()

datetime.datetime(2008, 7, 10, 13, 38, 48, 279539)

>datetime.today()-timedelta(1)

datetime.datetime(2008, 7, 9, 13, 38, 50, 939580)
Gary Herron

Thanks Gary! This works great. Now all I need to know is how to
plug the date into the datetime object from a string.

Ron

[Gary Herron]

RV wrote:

On Thu, 10 Jul 2008 13:39:29 -0700, Gary Herron
<gh*****@islandtraining.comwrote:

>The datetime module has what you need.

It has methods (with examples) on building a datetime object from a
string, and it has a object named timedelta, and the ability to subtract
a timedelta from a time.

For instance, the time right now and the time exactly one day ago:

>>>>from datetime import *
datetime.today()
>

datetime.datetime(2008, 7, 10, 13, 38, 48, 279539)

>>>>datetime.today()-timedelta(1)
>

datetime.datetime(2008, 7, 9, 13, 38, 50, 939580)
Gary Herron

Thanks Gary! This works great. Now all I need to know is how to
plug the date into the datetime object from a string.

Use
*strptime*( date_string, format)

The format argument uses %-fields to describe how to pull data out of
the date_string.
It uses the same set of %-fields as the time modules strftime function

Gary Herron

Ron

--
http://mail.python.org/mailman/listinfo/python-list

[Larry Bates]

RV wrote:

On Thu, 10 Jul 2008 13:39:29 -0700, Gary Herron
<gh*****@islandtraining.comwrote:

>The datetime module has what you need.

It has methods (with examples) on building a datetime object from a
string, and it has a object named timedelta, and the ability to subtract
a timedelta from a time.

For instance, the time right now and the time exactly one day ago:

>>>>from datetime import *
datetime.today()

datetime.datetime(2008, 7, 10, 13, 38, 48, 279539)

>>>>datetime.today()-timedelta(1)

datetime.datetime(2008, 7, 9, 13, 38, 50, 939580)
Gary Herron

Thanks Gary! This works great. Now all I need to know is how to
plug the date into the datetime object from a string.

Ron

I really shouldn't do this until you have put forth at least a little effort...
Type the following into the Python interpreter:

>>>import datetime
help(datetime.datetime.strptime)

Help on built-in function strptime:

strptime(...)
string, format -new datetime parsed from a string (like time.strptime()).
Note: Looking in Python manual or Googling for time.strptime (to get proper
format for YYYYMMDD)

dstr = "20070710"

dt = datetime.datetime.strptime(dstr, "%Y%m%d")

>>>dt

datetime.datetime(2008, 7, 10, 0, 0)

-Larry

[Michiel Overtoom]

Ron wrote:

Now all I need to know is how to
plug the date into the datetime object from a string.

You could use simple string manipulation:

>>import datetime
a="20081031"
d=datetime.date(int(a[0:4]),int(a[4:6]),int(a[6:8]))
d

datetime.date(2008, 10, 31)

>>print d

2008-10-31

Greetings,

[RV]

On Thu, 10 Jul 2008 20:04:27 -0400, RV <Ro**@Nospam.comwrote:

Gary, Larry, Michiel ,

Thanks very much, your helpful info has enabled me to get past a
learning bump.

Ron