Hi All,By default, each time you do d['1'] you get a *different* object. A shelve isn't very smart: it stores a string representation of your object (using pickle) and each time you ask for the object, it unpickles the stored string. When used as a persistence mechanism, it doesn't matter so much, the process that created the original instance may have died eons ago.
I want to store the class instance object variables persistenlty in one file
so that other file can also access for some filtering. I tired doing this
using the shelve module.
*Code:*
class A:
pass
import shelve
filename = 'test.db'
d = shelve.open(filename)
a = A()
print a
d['1'] = a
print d['1']
d.close()
*Output:*
<__main__.A instance at 0x018B56C0>
<__main__.A instance at 0x018B5760>
*Observation:*
I expect both the print statements to return the same value, The second
print statement just reads the dictonary, but still the adress (0x..) is
different from the first print statement. Can anyone tell me why. Also let
me know if you the way of getting same value both the times.
If object identity is important to you, you should remember to "fetch" the values only once in a single process, or use the writeback=True argument to the shelve constructor. But read the warning at <http://docs.python.org/lib/module-shelve.html>
pyd = shelve.open(filename, writeback=True)
pya = A()
pyd['1'] = a
pyx1 = d['1']
pyx2 = d['1']
pyx3 = d['1']
pyprint a, x1
<__main__.A instance at 0x00A3D5D0<__main__.A instance at 0x00A3D5D0>
pya is x1 is x2 is x3
True
--
Gabriel Genellina
